Question 12 of 20SubmWhat mass in grams of CH:OH (MM = 32.04 g/mol) would need to beadded to 330.1 g of water in order to lower the freezing point of waterby 12.0 °C? (Kf for water is 1.86 °C/m)136.C8+/-x 10092.7.

Given, Molar mass of CH3OH =32.04 g mol-1Mass of water =330.1g =0.330 Kg∆T = Depression in freezing…

Answered: s of CH:OH (MM = 32.04 g/mol) would…

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s of CH:OH (MM = 32.04 g/mol) would need t water in order to lower the freezing point of w water is 1.86 °C/m)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter11: Properties Of Solutions

Section: Chapter Questions

Problem 74E: The freezing point of 1-butanol is 25.50C and Kf is 9.1C kg/mol. Usually t-butanol absorbs water on...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

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