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9. A solution is prepared by dissolving 248 g of sucrose (C12H2½O11; MM = 342.0 g/mol) in 155 g water (MM = 18.0). What the vapor pressure of this solution at 55°C? The vapor pressure of water at 55°C is 118.1 torr. %3D

9. A solution is prepared by dissolving 248 g of sucrose (C12H2½O11; MM = 342.0 g/mol) in 155 g water (MM = 18.0). What the vapor pressure of this solution at 55°C? The vapor pressure of water at 55°C is 118.1 torr. %3D

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
Section: Chapter Questions
Problem 45P
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A solution is prepared by dissolving 248 g of sucrose (C12H2O11; MM = 342.0 g/mol) in 155 g water (MM = 18.0). What i the vapor pressure of this solution at 55°C? The vapor pressure of water at 55°C is 118.1 torr. 9. mosphere is D) 0.10 m C&H6 E) They all have the same boiling point. e the phase diagram shown at right to answer questions 12-14. What is the melting point of the substance if the pressure is 1200-
Transcribed Image Text:A solution is prepared by dissolving 248 g of sucrose (C12H2O11; MM = 342.0 g/mol) in 155 g water (MM = 18.0). What i the vapor pressure of this solution at 55°C? The vapor pressure of water at 55°C is 118.1 torr. 9. mosphere is D) 0.10 m C&H6 E) They all have the same boiling point. e the phase diagram shown at right to answer questions 12-14. What is the melting point of the substance if the pressure is 1200-
Expert Solution
Step 1

Moles of sucrose are,

Moles = mass ÷ molar mass

Moles = 248 g ÷ 342.0 g/mol

Moles = 0.73 mol

 

Moles of water are,

Moles = mass ÷ molar mass

Moles = 155 g ÷ 18 g/mol

Moles = 8.61 mol

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