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S (x2 – 1) · (4 – x²) dx is equal to O a) x^3/5 - 5 x^5/3 - 4x + c O b) 5 x^3/3 - x^5/5 - 4x + c O c) 5 x^3/3 - x*5/5 - 2x + c O d) 5 x^3/3 + x*5/5 - 4x + c

S (x2 – 1) · (4 – x²) dx is equal to O a) x^3/5 - 5 x^5/3 - 4x + c O b) 5 x^3/3 - x^5/5 - 4x + c O c) 5 x^3/3 - x*5/5 - 2x + c O d) 5 x^3/3 + x*5/5 - 4x + c

Elementary Linear Algebra (MindTap Course List)
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.2: Diagonalization
Problem 39E: Are the two matrices similar? If so, find a matrix P such that B=P1AP. A=[100020003]B=[300020001]
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S (x2 – 1) · (4 – x²) dx is equal to O a) x^3/5 - 5 x^5/3 - 4x + c O b) 5 x^3/3 - x^5/5 - 4x +c O c) 5 x^3/3 - x^5/5 - 2x + c O d) 5 x^3/3 + x*5/5 - 4x + c
Transcribed Image Text:S (x2 – 1) · (4 – x²) dx is equal to O a) x^3/5 - 5 x^5/3 - 4x + c O b) 5 x^3/3 - x^5/5 - 4x +c O c) 5 x^3/3 - x^5/5 - 2x + c O d) 5 x^3/3 + x*5/5 - 4x + c
If the order of matrix is m x p. And the order of B is pxn Then the order of matrix AB is nxp mxn Option 3 nxm
Transcribed Image Text:If the order of matrix is m x p. And the order of B is pxn Then the order of matrix AB is nxp mxn Option 3 nxm
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