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Asked Oct 15, 2019
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S/2
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S/2

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Expert Answer

Step 1

Given,

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x +2 dx +4

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Step 2

On simplification we get

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r +2 dx 2 x dx + x2 +4 x' +4 2 -d (1) x* + 4 -dr

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Step 3

Now consid...

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X -dx x24 Put x4 t Differentiating with respect to x, we get dt 2x0 dt 2x-dx = dt>x-dx 2 dt x x4 t 1dt 2 t log c Now replacingt =x +4, we get 2 1 x = log +4+c -(2) x 2 x +4 2

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Tagged in

Math

Calculus

Integration