Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius,and modifying the function accordingly.Sample output with input: 283.1510.0 C is 283.15 K283.15 K is 10.0 CLearn how our autograder works461710 3116374.qx3zqy71 def celsius_to_kelvin (value_celsius):value_kelvin = 0.0123453467 Your solution goes here """89 value_c= 10.010 print(f' {value_c} C is {celsius_to_kelvin(value_c)} K')11value_kelvin value_celsius + 273.15return value_kelvin111Run12 value_k = float(input())13 print(f' {value_k} K is {kelvin_to_celsius(value_k)} C')

Here's the modified kelvin_to_celsius function: def kelvin_to_celsius(value_kelvin):…

Answered: Sample output with input: 283.15 10.0 C…

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Sample output with input: 283.15 10.0 C is 283.15 K 283.15 K is 10.0 C

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius,
and modifying the function accordingly.
Sample output with input: 283.15
10.0 C is 283.15 K
283.15 K is 10.0 C
Learn how our autograder works
461710 3116374.qx3zqy7
1 def celsius_to_kelvin (value_celsius):
value_kelvin = 0.0
12345
3
4
6
7 Your solution goes here """
8
9 value_c= 10.0
10 print(f' {value_c} C is {celsius_to_kelvin(value_c)} K')
11
value_kelvin value_celsius + 273.15
return value_kelvin
111
Run
12 value_k = float(input())
13 print(f' {value_k} K is {kelvin_to_celsius(value_k)} C')

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