SAMPLING DISTRIBUTION The following are the monthly income of 5 workers working in a different company: 15 000, 18 000, 21 000, 24 000, and 28 000 (in pesos). A sample with size 2 is chosen to determine the average monthly income of the workers. Show your complete solution. Find the mean of the sample means. Compute the standard error of the sample means.

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
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Author:HOUGHTON MIFFLIN HARCOURT
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Chapter11: Data Analysis And Displays
Section: Chapter Questions
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SAMPLING DISTRIBUTION

The following are the monthly income of 5 workers working in a different company:

15 000, 18 000, 21 000, 24 000, and 28 000 (in pesos). A sample with size 2 is chosen to determine the average monthly income of the workers. Show your complete solution.

  1. Find the mean of the sample means.
  2. Compute the standard error of the sample means.
Solution 1.
Here, the population size is: N = 5 and the sample size is: n = 2.
Since, nothing has been mentioned we will consider simple random sampling with replacement (SRSWR).
In SRSWR, the number of possible sampling is
N"-52
=25
Answer: The total number of possible outcomes is 25.
Solution 2.
Here we construct the the table of all possible samples and the corresponding sample means.
Table of Sample Means
Sample values Sample mean
15000, 15000
15000
15000, 18000
16500
15000, 21000
18000
15000, 24000
19500
15000, 28000
21500
18000, 15000
16500
18000, 18000
18000
18000, 21000
19500
18000, 24000
21000
18000, 28000
23000
21000, 15000
18000
21000, 18000
19500
21000, 21000
21000
21000, 24000
22500
21000, 28000
24500
24000, 15000
19500
24000, 18000
21000
24000, 21000
22500
24000, 24000
24000
24000, 28000
26000
28000, 15000
21500
28000, 18000
23000
28000, 21000
24500
28000, 24000
26000
28000, 28000
28000
(Answer)
Transcribed Image Text:Solution 1. Here, the population size is: N = 5 and the sample size is: n = 2. Since, nothing has been mentioned we will consider simple random sampling with replacement (SRSWR). In SRSWR, the number of possible sampling is N"-52 =25 Answer: The total number of possible outcomes is 25. Solution 2. Here we construct the the table of all possible samples and the corresponding sample means. Table of Sample Means Sample values Sample mean 15000, 15000 15000 15000, 18000 16500 15000, 21000 18000 15000, 24000 19500 15000, 28000 21500 18000, 15000 16500 18000, 18000 18000 18000, 21000 19500 18000, 24000 21000 18000, 28000 23000 21000, 15000 18000 21000, 18000 19500 21000, 21000 21000 21000, 24000 22500 21000, 28000 24500 24000, 15000 19500 24000, 18000 21000 24000, 21000 22500 24000, 24000 24000 24000, 28000 26000 28000, 15000 21500 28000, 18000 23000 28000, 21000 24500 28000, 24000 26000 28000, 28000 28000 (Answer)
Solution 3.
There are 25 different possible samples, so the probability of each of the sample means is
Based on this we construct the following sampling distribution of the sample means.
Sampling Distribution of the Sample Means
Proba
Sample mean
bility
15000
1/25
16500
2/25
18000
3/25
19500
4/25
21000
3/25
21500
2/25
22500
2/25
23000
2/25
24000
1/25
24500
2/25
26000
2/25
28000
1/25
Total
(Answer)
Transcribed Image Text:Solution 3. There are 25 different possible samples, so the probability of each of the sample means is Based on this we construct the following sampling distribution of the sample means. Sampling Distribution of the Sample Means Proba Sample mean bility 15000 1/25 16500 2/25 18000 3/25 19500 4/25 21000 3/25 21500 2/25 22500 2/25 23000 2/25 24000 1/25 24500 2/25 26000 2/25 28000 1/25 Total (Answer)
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