Say you have a positively charged rod A of length L = 112 m (m stands for meter). Charge density of the rod is dA = 3.0 × 10-² C/m. (See figure 2(a). Figure is not drawn to scale.) Use the coulomb constant k = 8.987 × 10º N .m² /C² and magnitude of charge of one electron e = 1.6 × 10–19 C. d. L r Fig. 2(a) Fig. 2(b). (a) Find the Electric Field at point O which is located at distance r = 1.5 cm from rod A. (cm stands for centimeter or 10~2 m). The distance vector makes an angle of 90° with the rod. (See figure 2(a). Figure is not drawn to scale). x component y component of EA =

College Physics
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Chapter18: Electric Charge And Electric Field
Section: Chapter Questions
Problem 26PE: (a) Two point charges q1 and q23.00 m apart, and their total charge is 20 C. (a) If the force of...
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Say you have a positively charged rod A of length L = 112 m (m stands for meter). Charge density of the rod is dA = 3.0 × 10-² C/m. (See figure
2(a). Figure is not drawn to scale.)
Use the coulomb constant k = 8.987 × 10º N .m² /C² and magnitude of charge of one electron e = 1.6 × 10–19 C.
d.
L
r
Fig. 2(a)
Fig. 2(b).
(a) Find the Electric Field at point O which is located at distance r = 1.5 cm from rod A. (cm stands for centimeter or 10~2 m). The distance vector
makes an angle of 90° with the rod. (See figure 2(a). Figure is not drawn to scale).
x component y component of EA =
Transcribed Image Text:Say you have a positively charged rod A of length L = 112 m (m stands for meter). Charge density of the rod is dA = 3.0 × 10-² C/m. (See figure 2(a). Figure is not drawn to scale.) Use the coulomb constant k = 8.987 × 10º N .m² /C² and magnitude of charge of one electron e = 1.6 × 10–19 C. d. L r Fig. 2(a) Fig. 2(b). (a) Find the Electric Field at point O which is located at distance r = 1.5 cm from rod A. (cm stands for centimeter or 10~2 m). The distance vector makes an angle of 90° with the rod. (See figure 2(a). Figure is not drawn to scale). x component y component of EA =
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