Select a W12 shape for an axially loaded column to meet the following specifications: The length is 288inch, both ends are pinned, and there is bracing in the weak direction at a point 120 inch from the top. The service dead load is 142000lbs, and the service live load is 356000lbs. 1. Use LRFD. 2. Use ASD. Answer with text and/or attachments:
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- WRITE THE COMPLETE SOLUTION: Design a square column for the given concentric axial loads. The column is appliedwith total dead load of 800 kN and live load of 1400 kN. Use gross steel ratio ofapproximately 2.5%. fc’ = 17 Mpa , fy = 276 Mpa. Use 25mm bars for main bars and10 mm bars for ties.a. Compute for the required area of steel,b. Recommend the number of 25 mm bars.c. Calculate the required spacing of ties.d. Draw/sketch the cross-sectional detail of the columnDont copy or else i will report A truly supported beam 230 x 550 mm effective is reinforcerd with 4 16 - Fe 415. find total restrict nation load carried by the beam if span is five m effective. Use M 20.Use A992 steel and select a W14 shape for an axially loaded column to meet the following specifications: The length is 22 feet, both ends are pinned, and there is bracing in the weak direction at a point 10 feet from the top. The service dead load is 142 kips, and the service live load is 356 hips. a. Use LRFD. b. Use ASD.
- CAN SOMEONE PLEASE HELP ME SOLVE THIS PROBLEM WITH COMPLETE SOLUTION AND CLEAR HANDWRITING. I WILL GIVE A THUMBS UP IF DONE CORRECTLY A reinforced concrete beam 550mmx300mm with tensile reinforcements of 5-28mm is simply supported over a span of 8.92m with additional 2m overhang from the right support. Using steel covering of 65mm, fc’=28MPa and fs=138Mpa.Calculate the following requirements: Check whether the beam is safe from the following loadings: Wdl=30KN/m (beam weight included)– placed throughout the length of the beam Wll=20KN/m (along the simple span only) Wll=10KN/m (along the cantilever only) Pdl=50KN (located 2m from the left support) Pll= 75KN (located at the free end)I need help finding the compressive resistance of the column. A column is braced at mid height to prevent movement in the weak axis only. The column is 10m in length and pinned at both ends. The column has been specified as a W360 x 91 G40.21 345W steel. Given data: d=353mm , b=254mm, t=16.4mm, w=9.5mm, d-2t = 320mm, rx= 152mm, ry= 62.3mm, A = 11500mm^2, Fy= 345MPaA floor system is supported by WF A36 steel beams 8.6m long and spaced 3m on centers. The beams are simply supported at their ends and are laterally supported over their entire span. Assume compact section and neglect beam self-weight. The properties of the beam section are: d=518mm, tw=46mm, bf=347mm, tf=55mm, k=76mm, shape factor SF=1.20, Sx=8,439x103mm3. Use allowable deflection (1/360) of beam span. Calculate the SERVICE floor load in KPa that the beam can carry against DEFLECTION. Express your answer in 2 decimal places.
- Solve: Select the lightest 28 ft long W12 available to support a factored tensile load of Pu = 400 k. Assume there are 2 lines, (lines are 5” apart) of 7/8" bolts in each flange (4 lines total) and 3 bolts per line @ 4” o.c. and 4” to end. Assume A992 steel. Dimensions are from centers of bolt holes.Does the column shown below have enough available strength to support the given working loads?Use LRFD. Take E=20,232 ksi ,ry=2.3 in, K=1,Fy=59.0 ksi, Ag=32.7 inAn HSS 10 × 6 × 5 ⁄16 with Fy = 46 ksi is used as a column. The length is 16 feet. Both ends are pinned, and there is support against weak axis buckling at a point 6 feet from the top. a. Determine the design strength for LRFD. (kips) b. Determine the allowable strength for ASD. (kips)
- A reinforced concrete beam 550mmx300mm withtensile reinforcements of 5-28mm is simply supported over a span of 6.495m with additional 2m overhang from the right support. Using steel covering of 65mm, fc’=28MPa and fs=138Mpa.Calculate the following requirements: a)Check whether the beam is safe from the following loadings: Wdl=30KN/m (beam weight included)– placed throughout the length of the beam Wll=20KN/m (along the simple span only) Wll=10KN/m (along the cantilever only) Pdl=50KN (located 2m from the left support) Pll= 75KN (located at the free end)– A W460 × 177 is used as a compression member with one end fixed and the other end fixed against rotation but free to translate. The length is 3.70 meters. If A992 steel is used, what is the available compressive strength? Compute both the design strength for LRFD and the allowable strengthfor ASD.Use A992 steel and select a W shape for the following beam: Simply supported with a30-foot span, lateral support at each end and at the third-points, no service deadload, service LLis a 18-kips concentrated load at midspan. Don’t forget to check with self-weight (note: you donot need to worry about self-weight in calculating Cb). Assume that the middle third of the beamis the critical section. Assume that the live load deflection is limited to L/240. Please also checkfor bending capacity and shear capacity. You may use AISC Table 3-2 and/or Table 3-10 to checkfor bending and shear. Solve using LRFD only.