Self-test 16.2 A CH₂Cl molecule has a C-Cl bond length of 178 pm, a C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its rotational energy terms. [F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²; also F(J, K)/GHz = 13.3J (J + 1) + 137K²]

Self-test 16.2 A CH₂Cl molecule has a C-Cl bond length of 178 pm, a C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its rotational energy terms. [F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²; also F(J, K)/GHz = 13.3J (J + 1) + 137K²]

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter9: Atomic Absorption And Atomic Fluorescence Spectrometry

Section: Chapter Questions

Problem 9.7QAP

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UV Visible Spectroscopy

Spectroscopy refers to the absorption or emission of light or other radiations by matter. When a substance or chemical absorbs light or radiation, they reach an excited state followed by de-excitation or emission of the light or radiation forming distinct spectra. UV-visible spectroscopy or ultraviolet-visible refers to the absorption and emission in the ultraviolet and visible regions of the electromagnetic spectrum.

Question

Self-test 16.2 A CH335Cl molecule has a C-Cl bond length of 178 pm, a
C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its
rotational energy terms.
[F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²;
also F(J, K)/GHz = 13.3J (J + 1) + 137K²]

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