EspaA group of researchers wanted to examine some hypotheses about the behavior of people who bet onprofessional football games. One hypothesis was that people tend to bet according to how their picks turnedout the previous week: if the team a person picked to win one week actually won, the person might also pickthat team the next week, thinking that the team is "on a hot streak," or the person might bet against thatteam the next week, thinking that the team is "due for a loss." Another hypothesis was that there is no suchrhyme or reason to betting: there is no association between the bets that people make one week and thebets they make the next.In an experimental study, the researchers had each of their participants bet on each game of a professionalfootball season. The contingency table below contains some information from a random sample of 100 betsplaced on the Columbus Crush (picking them to win) during the last 14 games of the season (the Crush had7 wins and 7 losses over that period). This contingency table indicates, for each bet placed on the Crush,whether or not the team won and how the participant who placed the bet went the following week.. So, thereare two variables represented: result of picking the Crush ("Crush won" or "Crush lost") and bet placed thefollowing week ("picked Crush to win" or "picked Crush to lose").Each cell of the table contains three numbers: the first number is the observed cell frequency (fo); thesecond number is the expected cell frequency (fF) under the assumption that there is no dependencebetween the two variables result of picking the Crush and bet placed the following week; and the thirdnumber is the following value.fo-fE) (Oobserved cell frequency - Expected cell frequency )|fEExpected cell frequencyThe numbers labeled "Total" are totals for observed frequency. Part 1Fill in the missing values in the contingency table. Round your expected frequencies to two or more dec(So-fe)places, and round yourvalues to three or more decimal places.fESend data to ExcelBet placed the following weekPicked CrushPicked CrushTotalto winto lose4311Crush won54Result ofpicking the3016CrushCrush lost46Total7327100Part 2Answer the following to summarize the test of the hypothesis that there is no dependence betweevariables result of picking the Crush and bet placed the following week. For your test, use the 0.0significance.(a) Determine the type of test statistic touse,Type of test statistic: (Choose one) ▼(b) Find the value of the test statistic. (Round to two or more decimal places.)(c) Find the critical value for a test at the 0.05 level of significance. (Round totwo or more decimal places.)(d) Can we reject the hypothesis that there is no dependence between thevariables result of picking the Crush and bet placed the following week?Use the 0.05 level of significance.O Yes O No

Question

EspaA group of researchers wanted to examine some hypotheses about the behavior of people who bet onprofessional football games. One hypothesis was that people tend to bet according to how their picks turnedout the previous week: if the team a person picked to win one week actually won, the person might also pickthat team the next week, thinking that the team is &#34;on a hot streak,&#34; or the person might bet against thatteam the next week, thinking that the team is &#34;due for a loss.&#34; Another hypothesis was that there is no suchrhyme or reason to betting: there is no association between the bets that people make one week and thebets they make the next.In an experimental study, the researchers had each of their participants bet on each game of a professionalfootball season. The contingency table below contains some information from a random sample of 100 betsplaced on the Columbus Crush (picking them to win) during the last 14 games of the season (the Crush had7 wins and 7 losses over that period). This contingency table indicates, for each bet placed on the Crush,whether or not the team won and how the participant who placed the bet went the following week.. So, thereare two variables represented: result of picking the Crush (&#34;Crush won&#34; or &#34;Crush lost&#34;) and bet placed thefollowing week (&#34;picked Crush to win&#34; or &#34;picked Crush to lose&#34;).Each cell of the table contains three numbers: the first number is the observed cell frequency (fo); thesecond number is the expected cell frequency (fF) under the assumption that there is no dependencebetween the two variables result of picking the Crush and bet placed the following week; and the thirdnumber is the following value.fo-fE) (Oobserved cell frequency - Expected cell frequency )|fEExpected cell frequencyThe numbers labeled &#34;Total&#34; are totals for observed frequency. Part 1Fill in the missing values in the contingency table. Round your expected frequencies to two or more dec(So-fe)places, and round yourvalues to three or more decimal places.fESend data to ExcelBet placed the following weekPicked CrushPicked CrushTotalto winto lose4311Crush won54Result ofpicking the3016CrushCrush lost46Total7327100Part 2Answer the following to summarize the test of the hypothesis that there is no dependence betweevariables result of picking the Crush and bet placed the following week. For your test, use the 0.0significance.(a) Determine the type of test statistic touse,Type of test statistic: (Choose one) ▼(b) Find the value of the test statistic. (Round to two or more decimal places.)(c) Find the critical value for a test at the 0.05 level of significance. (Round totwo or more decimal places.)(d) Can we reject the hypothesis that there is no dependence between thevariables result of picking the Crush and bet placed the following week?Use the 0.05 level of significance.O Yes O No

Accepted Answer

We complete the table using the given formula.
It is known that,
Expected frequency= (row total*…