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Asked Nov 21, 2019
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Set up an integral, but do not evaluate, that would give the surface area of the surface S
parametrized by (u, v) = (cos(u), sin(u) +cos(v), sin(v)), 0 u 2T, 0 v<T/4.
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Set up an integral, but do not evaluate, that would give the surface area of the surface S parametrized by (u, v) = (cos(u), sin(u) +cos(v), sin(v)), 0 u 2T, 0 v<T/4.

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Expert Answer

Step 1

From the given data, the surface area of the ...

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D(u,v) (cos(u), sin(u)+cos(v), sin(v)), 0<us27, 0svs 4

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