Show that the differential equation x³y² + x(1+yº)y' = 0 is not exact, but becomes exact when multiplied by the integrating factor 1 μ(x, y) = Then solve the equation. xy? The given equation is not exact, because My = 726 y which is different from N=1+y6 After multiplication with u(x, y), the equation is exact, because then My = Nx = 0 The general solution of the differential equation is given implicitly by 1 =c, for any constant c, where y > 0. y6 + 6 ln(y)

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Chapter1: Functions And Models
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Show that the differential equation x³y² + x(1+yº)y' = 0 is not
exact, but becomes exact when multiplied by the integrating factor
Then solve the equation.
μ(x, y) =
=
1
xy7
The given equation is not exact, because My
which is different from N = 1+y6
because My = 7 x6 yº
After multiplication with u(x, y), the equation is exact, because then
My = Nx
y6
= 0
The general solution of the differential equation is given implicitly by
1
= c, for any constant c, where y > 0.
+ 6 ln(y)
Transcribed Image Text:Show that the differential equation x³y² + x(1+yº)y' = 0 is not exact, but becomes exact when multiplied by the integrating factor Then solve the equation. μ(x, y) = = 1 xy7 The given equation is not exact, because My which is different from N = 1+y6 because My = 7 x6 yº After multiplication with u(x, y), the equation is exact, because then My = Nx y6 = 0 The general solution of the differential equation is given implicitly by 1 = c, for any constant c, where y > 0. + 6 ln(y)
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