Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (½) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor ½.

University Physics Volume 2
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ISBN:9781938168161
Author:OpenStax
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Chapter8: Capacitance
Section: Chapter Questions
Problem 61P: The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.60 and a...
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Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (½) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor ½.

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