Show that the general solution of y(4) − y = 0 can be written as y=c1cost+c2sint+c3cosht+c4sinht. Determine the solution satisfying the initial conditions y(0) = 0, y′(0) = 0, y″(0) = 1, y‴(0) = 1. Why is it convenient to use the solutions cosh t and sinh t rather than et and e−t ?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Show that the general solution of y(4) − y = 0 can be written as

y=c1cost+c2sint+c3cosht+c4sinht.

Determine the solution satisfying the initial conditions y(0) = 0, y′(0) = 0, y″(0) = 1, y‴(0) = 1. Why is it convenient to use the solutions cosh t and sinh t rather than et and e−t ?

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