M2.2-answer number 1 only-complete solution POF Activity 1.2 - Electric Flux and Ga xActivity 2.1 - Electric Potential.pd xO Activity 2.2 - Capacitance and Di x+->O File | C:/Users/Danica%20Martinez/Desktop/Activity%202.2%20-%20Capacitance%20and%20Dielectrics.pdf...a Agoda G GmailYouTube G Maps O Translatep MODULE 4.2 Electr.INSTRUCTIONS:Show your complete solution to each problem on a short bond paper.Answers must be expressed in engineering notation (when the exponent of the base 10 multiplieris not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.)Example: 0.06N or 6.0x10-2 N must be expressed to 60x10-3 N or 60mN1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relativepermittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mmthick and of relative permittivity ɛr . If the equivalent capacitance is one-half of the original capacitance, findthe value of ɛr.2. In the given network, each capacitor has C = 4.00 µF andVah = +28. 0 V. Calculate the:a. Total capacitanceb. Charge on each capacitorc. Potential difference on each capacitor3. A 20 µF capacitor is charged to 120 V and then disconnected from the power supply. If a second unchargedcapacitor with capacitance of 50 µF is connected across the first capacitor, what would be the resultingvoltage across their parallel combination?4. A parallel-plate capacitor in air has a plate separation of 1.35 cm and a plate area of 35.0 cm2. The platesare charged to a potential difference of 150 V and disconnected from the source. The capacitor is thenimmersed in distilled water. Assume the liquid is an insulator. Determine:a. the charge on the plates before and after immersionb. the capacitance and potential difference after immersionc. the change in energy of the capacitor after immersion5. Find the relative permittivity ɛr of the dielectric material present in a parallel-plate capacitor if:A = 0.12 m2, d = 80 µm, V =12 V, U =1 µJ11:20 amP Type here to search32°C HazeA ENG19/03/2022

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Show your complete solution to each problem on a short bond paper. Answers must be expressed in engineering notation (when the exponent of the base 10 multiplier is not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.) Example: 0.06N or 6.0x102 N must be expressed to 60x10-3 N or 60mN 1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity ɛr . If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. 2. In the given network, each capacitor has C = 4.00 µF and +?8 OK Calculate the

Show your complete solution to each problem on a short bond paper. Answers must be expressed in engineering notation (when the exponent of the base 10 multiplier is not a multiple of 3, press ENG or SHIFT+ENG, whichever the case.) Example: 0.06N or 6.0x102 N must be expressed to 60x10-3 N or 60mN 1. A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity ɛr . If the equivalent capacitance is one-half of the original capacitance, find the value of ɛr. 2. In the given network, each capacitor has C = 4.00 µF and +?8 OK Calculate the

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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