Question
Asked Sep 18, 2019
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Prove this limit via trigonometric limits

Sin Sxsin
XSin 8
Lin
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Sin Sxsin XSin 8 Lin

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Expert Answer

Step 1

The give expression is,

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sin 5x sin 7x lim x0 ..1) xsin 8.x

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Step 2

Since we know that,

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lim sinr x0 =1 x

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Step 3

Multiply numerator  and denominator of equation 1 by 8x...

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sin 5x lim x0 sin 5.x sin 7x lim sin 7x 8x 35x 8.x 35x X X 8x 35x X X sin 8.x 7x X sin 8x 5.x 8.x sin 5xxlim =lim sin 7x xlim 7x 35.x xlim 8x 8.x sin 8x 5x x0 x-0 x0 35 =1x1x1xlim x0

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Tagged in

Math

Calculus

Limits