Since elderly people may have difficulty standing straight, a study aims to predict overall height from height to the knee. Here are data (in centimeters, cm) for five elderly men. Knee Height (cm) 57.7 47.4 43.5 44.8 Overall Height(cm) 192.1 153.3 146.4 162.7 Let's assume a regression model Overall height = Bo + B₁ x Knee height + 1. Which R command should you use to fit the model if you have defined variables as knee = c(57.7, 47.4, 43.5, 44.8, 55.2) overall = c(192.1, 153.3, 146.4, 162.7, 169.1) 55.2 169.1 (a) 1m (knee ~ overall) (b) lm (overall ~ knee) (c) t.test(overall, knee) (d) t.test (knee, overall)

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.3: Least Squares Approximation
Problem 31EQ
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Please solve both subparts of the question. Part 1 is one image and part 2 is the other one. Thanks!

Since elderly people may have difficulty standing straight, a study aims to
predict overall height from height to the knee. Here are data (in centimeters,
cm) for five elderly men.
Knee Height (cm) 57.7 47.4 43.5 44.8
Overall Height (cm) 192.1
192.1 153.3 146.4 162.7
Let's assume a regression model
Overall height = Bo + B₁ x Knee height + e
1. Which R command should you use to fit the model if you have defined
variables as
I
knee = c(57.7, 47.4, 43.5, 44.8, 55.2)
overall = c(192.1, 153.3, 146.4, 162.7, 169.1)
(a) 1m (knee overall)
(b) lm (overall ~ knee)
(c) t.test(overall, knee)
(d) t.test (knee, overall)
55.2
169.1
~
Transcribed Image Text:Since elderly people may have difficulty standing straight, a study aims to predict overall height from height to the knee. Here are data (in centimeters, cm) for five elderly men. Knee Height (cm) 57.7 47.4 43.5 44.8 Overall Height (cm) 192.1 192.1 153.3 146.4 162.7 Let's assume a regression model Overall height = Bo + B₁ x Knee height + e 1. Which R command should you use to fit the model if you have defined variables as I knee = c(57.7, 47.4, 43.5, 44.8, 55.2) overall = c(192.1, 153.3, 146.4, 162.7, 169.1) (a) 1m (knee overall) (b) lm (overall ~ knee) (c) t.test(overall, knee) (d) t.test (knee, overall) 55.2 169.1 ~
2. Test the significance of explanatory variable.
(a) There is no evidence that the explanatory variable is significant
(p-value 20.1)
(b) There is some evidence that the explanatory variable is significant
(0.05 ≤ p-value < 0.1)
I
(c) There is strong evidence that the explanatory variable is signifi-
cant
(0.01 ≤ p-value < 0.05)
(d) There is very strong evidence that the explanatory variable is
significant
(0.001 ≤ p-value < 0.01)
Transcribed Image Text:2. Test the significance of explanatory variable. (a) There is no evidence that the explanatory variable is significant (p-value 20.1) (b) There is some evidence that the explanatory variable is significant (0.05 ≤ p-value < 0.1) I (c) There is strong evidence that the explanatory variable is signifi- cant (0.01 ≤ p-value < 0.05) (d) There is very strong evidence that the explanatory variable is significant (0.001 ≤ p-value < 0.01)
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