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- A vessel going from salt to freshwater sinks 5cm, then after burning 500kn of coal rises 2.5cm. What is the original weight of the vessel? Assume that the cross-sectional area of the vessel near the water surface is constant. Unit wt of seawater=10.10 kN/m^3.How much energy would it take to raise a can of soda (m = 350 grams) to average cruising altitude (35,000 ft)? Our textbook states that a gallon of gasoline contains 1.2×108 Joules of energy. Assuming 100% efficiency, how many gallons of gasoline would it take to raise the can of soda to 35,000 ft? A calorie is the amount of energy needed to raise the temperature of 1 gram of water by 1 Celsius degree (4.186 J). A nutritional Calorie is actually 1000 calories (1 Cal = 1 kcal). How many Calories of energy does it take to raise the can of soda to cruising altitude? Given that a can of Coke is about 140 Calories, how many cans of coke does it take to raise a can of coke to cruising altitude?A 100 grams non-uniform meter stick is found to balance on a knife edge at the 60-cm mark. Where is the position of the 60 grams mass need to hang to balance the meter stick at 50-cm marker? In the above problem, if you were given another 20-gram mass, (a) where do you hang it on left side, (b) where do you hang it on right side to keep the meterstick balance. If you can't, then justify your answer.
- A tremendous force is generated when waterfreezes into ice and expands in volume by 9.0%. Suppose a 1.000-m3cube of liquid water freezes into ice that is 1.000 m on a side by1.090 m tall. How many 68-kg students would the ice be able tolift? Determine this by calculating the amount of force on the top1.000-m2face that would be required to squeeze 1.090 m3of iceback to 1.000 m3, assuming all of the volume change occurs alongthe vertical directionGive me right solution with clear calculations. A closed cylindrical tank 1.89m high and 0.99m in diameter contains water of height 1.35m. When the angular velocity is constant at 20rad/sec What is the area (m 2) uncovered at the bottom? A. 0.1 B. 0.3 C.0.7 D. 0.07 If it is rotated at 15rad/sec and the air has a pressure of 200kPa what is the minimum pressure at the bottom of the tank in KPa? A. 245.10 B.145.10 C.201.45 D.210.54A vessel cylindrical in shape and closed at the top and bottom is 200 mm in diameter and 0.15 m in height. The vessel is completely filled with water. If it is rotated about its vertical axis with a speed of 200 r.p.m., what is the total pressure force (in N) exerted by water at bottom of the vessel? CHOICES: a.7.09 b.10.35 c.80.6 d.34.4
- Using Newton's second law, the movement of a body in a viscous fluid can be modeled. For this case it will be a one-dimensional movement. ec.1) F -FR = ma F: Force applied to the body. FR: Resistance that opposes the fluid to the movement. m: body mass a: body acceleration For a sphere with initial radius R0 = 1 meter and density 8960 kg/m^3 to which a constant force of 3 Kilo Newtons is applied, it is requested: Using Euler's method, find the velocity as a function of time for the first 5 seconds of movement, considering that v(0) = 10 m/s. Use a 1 second step. For this case use: ec.2) FR = 210Rv R: Radius of the sphere. v: velocity Where, in addition, the sphere disintegrates as time passes in this fluid, so its radius is given by the following function: ec.3) R = R0*e^(-t/250)On October 21, 2001, Ian Ashpole of the United Kingdom achieved a record altitude of 3.35 km (11,000 ft) powered by 600 toy balloons filled with helium. Each filled balloon had a radius of about 0.47 m and an estimated mass of 0.32 kg. (a) Estimate the total buoyant force on the 600 balloons. (Enter your answer to at least two decimal places.) kN(b) Estimate the net upward force on all 600 balloons. kN(c) Ashpole parachuted to Earth after the balloons began to burst at the high altitude and the system lost buoyancy. Why did the balloons burst? Atmospheric pressure at this high or low altitude is much lower or higher than at the Earth's surface.At the surface of a freshwater spring, a manatee with a small amount of air in its lungs is neutrally buoyant. The manatee now dives to a depth of 10 m. At this greater depth, the buoyant force isA. Less than the weight force.B. The same as the weight force.C. Greater than the weight force.
- Two homogeneous spheres of mass M radius R joined by a bar of length L = 2R, negligible mass, and suspended from its geometric center by a rope such that when rotated ϕ exerts torque −kϕ with k torsion coefficient of the wire. The air exerts dissipative effect F = −6πηv on each sphere, where η is the viscosity of the air and v is the linear velocity of each sphere. If I0 = 25MR2 is the moment of inertia of a sphere with respect to its center of mass (image 1)determine the equation of motion of the pendulum. (image 2)Q) A body with a mass of 15 kilograms is moving with a velocity of 3 meters/secand. If a force of 15 N is applied to the body, what its velocity aller 5 socunds? discuss your results please.Free-surface problems are driven by gravity. Why do somany of the formulas in this chapter contain the squareroot of the acceleration of gravity?