Using this equation: P4 + 6F2-4PF3 and the BCA table below, how many moles of P4 are needed to produce1.35 moles of PF3RxnP46F24PF3BCA1.35O 1.35 molesO XSO 0.34 molesO 5.4 moles

we have to calculate the moles of P4 needed

Answered: sing this equation: P4 + 6F2-4PF3 and…

sing this equation: P4 + 6F2-4PF3 and the BCA table below, how many moles of P4 are needed to produce 35 moles of PF3 Rxn P4 6F₂ 4PF3 B C A 1.35 1.35 moles 0.34 moles 5.4 moles Oxs

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions

Section: Chapter Questions

Problem 104GQ

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Using this equation: P4 + 6F2-4PF3 and the BCA table below, how many moles of P4 are needed to produce
1.35 moles of PF3
Rxn
P4
6F2
4PF3
B
C
A
1.35
O 1.35 moles
O XS
O 0.34 moles
O 5.4 moles

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