Snow and ice sublime spontaneously when the partialpressure of water vapor is below the equilibrium vaporpressure of ice. At 0°C the vapor pressure of ice is0.0060 atm (the triple-point pressure of water). Takingthe enthalpy of sublimation of ice to be 50.0 kJ mol-1,calculate the partial pressure of water vapor belowwhich ice will sublime spontaneously at-15°C.

Q: For a particular reaction, the equilibrium constant at 25 Celsius is known to be 1254. If the…

A: The relation between equilibrium constant, temperature and enthalpy change is given by van't Hoff…

Q: A process cannot be spontaneous if_ O it is exothermic, and there is an increase in disorder O it is…

A: ∆G= ∆H -T∆S for a spontaneous reaction free energy should be always negative.

Q: Select the substance expected to have the largest standard entropy value at 25°C. Assume the same…

A: Ans

Q: At equilibrium, the change in Gibbs Free energy (DG) equals O RTINK O the standard Gibbs Free Energy…

A: AT EQUILIBRIUM CONDITION GIBBS FREE ENERGY IS EQUAL TO ZERO AS AT EQUILIBRIUM THERE IS NO NET WORK…

Q: Synthetic diamonds are made under conditions of high temperature (2000 K) and high pressure (1010…

A: Given, Synthetic diamonds are made under conditions of high temperature (2000 K) and high pressure…

Q: For the reaction H2S(g) + 2H20(1)3H2(g) + SO2(g) AH° = 295.4 kJ and AS° = 294.7 J/K The equilibrium…

A:

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: Gibbs free energy for reversible reactions at any point can be easily estimated with the use of…

Q: Consider the following reaction at 298 K: Si(s) + 2 Cl2(g) → SiCl4(g) Calculate the following: a)…

A: Introduction :  A thermodynamic system can be defined as a body which is confined in a space and…

Q: For pentane, the ∆H° of vaporization is 26.22 kJ/mol and the ∆S° of vaporization is 87.88 J/mol･K.…

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Q: The ∆G° of vaporization for cyclohexane at 298 K and 1.00 atm is -0.2164 kJ/mol. Calculate the…

A: Given that:                   Temperature for the process = 298 K                               ∆G°…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: The equilibrium reaction given is, => C2H6 (g) + H2 (g) ↔ 2 CH4 (g)  Given: Temperature = 298 K…

Q: 1. Consider the following reaction at 25.0°C: 2NO,(g) =N,O,(g) The values of AH° and AS° are -58.03…

A: The reaction

Q: As O2(l) is cooled at 1 atm, it freezes at 54.5 K to form solid I. At a lower temperature, solid I…

A: The expression that will be used to determine the temperature at which solids I and II are in…

Q: For a particular reaction, Δ?=−238.4 kJ/molΔ⁢H=−238.4 kJ/mol and Δ?=−80.0 J/(mol·K).Δ⁢S=−80.0…

A:

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A: Formula used:-  ∆G = ∆G° + RT ln Kp Where Kp is pressure of product/pressure of reactant

Q: The ∆G° of vaporization for butane at 298 K and 1.00 atm is -2.125 kJ/mol. Calculate the pressure of…

A: The equilibrium is Butane(l)↔Butane(g)

Q: For 2-methylbutane, the ∆H° of vaporization is 25.22 kJ/mol and the ∆S° of vaporization is 84.48…

A: Given:  The ∆H° of vaporization for 2-methylbutane =  25.22 kJ/mol The ∆S° of vaporization for…

Q: if a sample of aluminum at 50oC is added to 30.0 mL of water at 22oC, and at a equilibrium the…

A: Consider the given information is as follows; Aluminum: Mass of aluminum = ?…

Q: Consider a mixture of 75.00 g water at room temperature 23.0 0C and 25.0 g water at 95.0 0C.…

A:

Q: Find the temperature (in K) above which a reaction with a AH of 53.00 kJ/mol la AS of 100.0 J/mol-K…

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Q: A 1.00-mole sample of ammonia (CPm 35.66 J K mol') at 14.0 atm and 25 °C in a cylinder fitted with a…

A: #3: We are given two different states, one is before expansion and the next after expansion against…

Q: Consider the reaction: - ICI:(s). The AG° of the reaction is -17.09 kJ/mol. IC(g) + Cl2(g) -…

A: The relationship between ∆G and ∆G° of the reaction is : ∆G = ∆G° + RT ln K••••••(1) Here, R is…

Q: A particular reaction has a ΔHo value of -141. kJ and ΔSo of -104. J/mol K at 298 K. Calculate ΔGo…

A: We are given :648. K Change in enthalpy (ΔHo)  =   -141. kJ change in entropy (ΔSo)  = -104. J/ K =…

Q: For the vaporization of oxygen, O2 (1) → O2 (9) AĦ° = 18.5_kJ mol J AS° : 205.2- mol·K and This…

A: Introduction: Gibbs free energy: A state function Gibbs free energy determines whether or not a…

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A:

Q: Consider the vaporization of liquid water to steam at a pressure of 1 atm.In what temperature range…

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Q: Kyanite, sillimanite,and andalusite all havethe formula Al₂SiO₅.Each is stable under dif-ferent…

A: a)  All the three minerals are having equal free energy at equilibrium.   b)  Among the three…

Q: Consider these reactions: Reaction 1: H2(g)+Cl2(g)⟶2HCl(g)ΔH=−184.6 kJ  Reaction 2:…

A: Change in enthalpy : ΔH = + 66.4 kJ                                      ΔH = + 66400 J Change in…

Q: Determine Kç at 298 K for the reaction % N2(g)+ ½ O2(g) + ½ Cl2(g)- following data set at 298K. 7. +…

A:

Q: H2 (g )- C6 H6 ( ) at 25°C, the standard enthalpy change is -631 kJ and the standard entropy change…

A: Chemical Reaction =>    3C2 (s)  + 3H2 (g)  ----> C6H6 (l) Standard enthalpy change is -631 kJ…

Q: For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all…

A:

Q: Consider the physical process at 1 atm pressure: Br2 (l) -->  Br2 (g)   where  ΔHo = 31.0 kJ/mol and…

A: We can solve Given problem by using following equation ∆G= ∆H - T∆S Where ∆G = Gibbs free energy…

Q: Calculate the entropy change of the surroundings when 15.2 g of solid iodine sublimes at 25.0 °C.…

A:

Q: The following reaction has these standard thermodynamic parameters: AHPrxn = -36.1 kJ/mol and…

A: Given data : ∆H0= -36.1KJmol-1 ∆Srex= -69.8Jmol-1K-1

Q: The molar heats of fusion and vaporization of benzene are 10.9 kJ/mol and 31.0 kJ/mol, Calculate the…

A: Given data molar heats of fusion :  ∆Hfus=10.9 KJ/mole molar heats of vaporization : ∆Hv=31.0…

Q: The temperature

A: we know the thermodynamic equation:                               ∆G°=∆H° - T∆S°…

Q: A particular reaction has a ΔHo value of -157. kJ and ΔSo of -343. J/mol K at 298 K. Assuming that…

A: ∆H° = -157 kJ/mol ∆S° = -343 J/mol-K T = 298 K  We have to determine the temperature when…

Q: Consider the reaction: ICI(g) + Cl₂(g) → ICI (s). The AG° of the reaction is -17.09 kJ/mol.…

A: we have to calculate the value of ∆G

Q: 17.110 Synthetic diamonds are made under conditions of high temperature (2000 K) and high pressure…

A: Phase diagram is a graphical representation showing the limiting conditions for solid, liquid, and…

Q: Benzene is a liquid under standard conditions. The standard enthalpy and entropy changes for the…

A: Since enthalpy change is positive that is the reaction is undergoing absorption of heat. Due to…

Q: For a new reaction A+B--> C an equilibrium constant of 3.2x10-6 was obtained at 284 K.  In a…

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Q: At 1 atm pressure, CO2(s) sublimes at -78 °C. Is this processspontaneous at -100 °C and 1 atm…

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Q: A certain reaction has AH = -25 kJ/mol and AS = -50 J/mol·K. At what temperature range is the…

A:

Q: Consider the reaction: ICl(g) + Cl₂(g) → ICl₃(s). The ∆G° of the reaction is -17.09 kJ/mol.…

A:

Q: The standard state Gibb's energy and entropy changes are known for the reaction: 2H,S(g) + 30,(g)…

A: Formula  ΔG° = ΔH° - TΔS° - 120 x 103 = ΔH° - 298 x 52  ΔH° = -120000 + 15496 = - 104504 J/mol ΔH° =…

Q: Consider the reaction 2N,0,) (3)o + (8)'ONE at 25°C for which the following data are relevant: AH so…

A: The answer to this question is as follows--------- enthalphy change = enthalphy of formation of…

Q: melting

A: Water freezes at temperatures below 0 oC. At temperatures where phase changes take place (boiling…