Soil CompactionStandard proctor testDry density (kg/m³)Water content (%)Problem Set No. 716919.311.81. The data from standard and modified1715proctor test on a soil sample (density ofsolids: 2680 kg/m³) are provided below.1755174714.317.620.81685161923a) Plot the compaction curves (bothstandard and modified in one graph)Modified proctor testDry density (kg/m³)Water content (%)18739.3b) Establish the MDD and OMC for191012.8each test1803169915.5c) Plot the 100% saturation curve. AlsO18.7plot the 70& saturation curve164121.1

MOISTURE CONTENT DRY DENSITY 100 % SATURATION LINE 70% SATURATION LINE 9.3 1691 2145.304…

Soil Compaction Standard proctor test Dry density (kg/m’) | Water content (%) Problem Set No. 7 1691 9.3 11.8 1. The data from standard and modified 1715 1755 1747 1685 14.3 proctor test on a soil sample (density of solids: 2680 kg/m³) are provided below. 17.6 20.8 23 Modified proctor test 1619 a) Plot the compaction curves (both standard and modified in one graph) Dry density (kg/m’) 1873 1910 Water content (%) 9.3 b) Establish the MDD and OMC for 12.8 each test 1803 1699 15.5 c) Plot the 100% saturation curve. Also plot the 70& saturation curve 18.7 21.1 1641

Soil Compaction Standard proctor test Dry density (kg/m’) | Water content (%) Problem Set No. 7 1691 9.3 11.8 1. The data from standard and modified 1715 1755 1747 1685 14.3 proctor test on a soil sample (density of solids: 2680 kg/m³) are provided below. 17.6 20.8 23 Modified proctor test 1619 a) Plot the compaction curves (both standard and modified in one graph) Dry density (kg/m’) 1873 1910 Water content (%) 9.3 b) Establish the MDD and OMC for 12.8 each test 1803 1699 15.5 c) Plot the 100% saturation curve. Also plot the 70& saturation curve 18.7 21.1 1641

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.14P

See similar textbooks

Similar questions

Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30, PL = 10) ? Use this given M=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 gM=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 g Sieve No. Opening Size (mm) Mass retained (g) %Mass retained=MiM×100=MiM×100 %Cumulative mass retained % Finer 4 4.750 28 =28617×100%=4.54%=28617×100%=4.54% 4.54 95.46 10 2.0 42 =42617×100%=6.81%=42617×100%=6.81% 11.35 88.65 20 0.850 48 =48617×100%=7.78%=48617×100%=7.78% 19.13 80.87 40 0.425 128 =128617×100%=20.74%=128617×100%=20.74% 39.87 60.13 60 0.250 221 =221617×100%=35.82%=221617×100%=35.82% 75.69 24.31 100 0.150 86 =86617×100%=13.94%=86617×100%=13.94% 89.63 10.37 200 0.075 40 =40617×100%=6.48%=40617×100%=6.48% 96.11 3.89 Pan 24 =24617×100%=3.89%=24617×100%=3.89% 100 0 Now, to plot the GSD curve, the % finer is kept on the vertical axis and the opening size are kept on the horizontal axis -…
15. The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0018 m3 Mass of moist soil from hole = 3.44 kg Water content = 12.30% Max. dry unit weight from a laboratory compaction test = 19.94 kN/m3 Determine the relative compaction, in percent. Round off to two decimal places. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
Calculate % Silt using the following values; a. Weight of soil= 50 g b. HR reading at 40 sec.= 25 c. Temp at 40 sec= 25 oCd. HR at 2 hrs= 16 e. Temp at 2 hrs= 26 * A. 17.28 B. 17.25 C 17.22 D. 17.19
How does the dry unit weight, differ from the unit weight ? Why is the Proctor method of assessing soil compaction based on the dry unit weight and not the unit weight?
Calculate the Gs of soil sample - Mass of empty clean pycnometer= 41.76 gm Mass of empty clean pycnometer + dry soil = 67.52 gm Mass of pycnometer + dry soil + water = 157.62 gm Mass of pycnometer + water =? Gs =? Write your comment about types of soil according to the result of Gs .
arrow_forward Question A fine-grained soil has 60% clay with LL 220%, PL 545%, and a natural water content of 6%. A standard Proctor test was carried out in the laboratory and the following data were recorded Diameter of mold = 101.40 mmHeight of mold = 116.70 mmMass of mold = 4196.50 gramSpecific gravity, Gs = 2.69 a) Determine the maximum dry unit weight and optimum water content.b) If the desired compaction in the field is 95% of the standard Proctor test results, what values of dry unit weight and water content would you specify?c) Explain why you select these values.d) What field equipment would you specify to compact the soil in the field, and why?e) How would you check that the specified dry unit weight and water content are achieved in the field? I Need The Answer of part (d) and (e)...
Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a 25g soil sample (a. Ca++= 2.23 m.e; b. Mg++=1.32 m.e.; c. Na+= 1.98 m.e.; d. K+= 1.87 m.e.; e. H+= 1.27 m.e.; f. Al+++= 0.11 m.e.; g. NH4+= 2.3 m.e.; h. NO3-= 1.5 m.e.
You are checking a field-compacted layer of soil. The laboratory control curve has the following values: gd (kN/m3) w (%) 16.34 14 16.57 16 16.65 18 16.50 20 16.26 22 15.87 24 The specification for compaction states that the field-compacted soil must be at least 95% of the maximum control density and within of the optimum moisture for the control curve. You dig a hole 1m3 in the compacted layer and extract a sample that weighs 17.2 kN wet and 14.1 kN dry. (a) What is the compacted gd? The compaction w? The percent compaction? Does the sample meet the specifications? (b) If the specific gravity is 2.68, what is the compacted degree of saturation? If the sample were saturated at constant density, what would be the water content?
Laboratory tests performed on a saturated alluvial subgrade soil gave the following information: In situ water content = 11.9%, Specific gravity = 2.65, Soil size distribution: D100 = 51 mm, D75 = 30 mm, D60 = 20 mm, D45 = 15 mm, D30 = 8 mm, D10 = 4.76 mm, D8 = 2 mm, D4 = 0.08 mm, < 2 m = 4% a. Is this soil well graded? Classify it by the AASHTO and Unified systems b. Using the sieve analysis soil data and the classification systems, estimate for a total of 100% the approximate percentages of coarse aggregate (gravel), fine aggregate (sand), silts, and clays?
identification 10 to 11 10. It is a characteristic of soil when liquidity index is greater than 1. 11. write the formula in determining relative compaction. this subject is related to geothecnical engineering (soil mech)
The following data were obtained by conducting liquid limit and plastic limit tests on a soil collected from the site. Liquid limit tests: Plastic limit test: PL = 19.3% a. Draw the flow curve and determine the liquid limit. b. Using the Casagrande plasticity chart (Figure 4.21), determine the soil type.
Since laboratory or field experiments are generally expensive and time consuming, geotechnical engineers often have to rely on empirical relationships to predict design parameters. Section 6.6 presents such relationships for predicting optimum moisture content and maximum dry unit weight. Let us use some of these equations and compare our results with known experimental data. The following table presents the results from laboratory compaction tests conducted on a wide range of fine-grained soils using various compactive efforts (E). Based on the soil data given in the table, determine the optimum moisture content and maximum dry unit weight using the empirical relationships presented in Section 6.6. a. Use the Osman et al. (2008) method [Eqs. (6.15) through (6.18)]. b. Use the Gurtug and Sridharan (2004) method [Eqs. (6.13) and (6.14)]. c. Use the Matteo et al. (2009) method [Eqs. (6.19) and (6.20)]. d. Plot the calculated wopt against the experimental wopt, and the calculated d(max) with the experimental d(max). Draw a 45 line of equality on each plot. e. Comment on the predictive capabilities of various methods. What can you say about the inherent nature of empirical models?