Problem 2: From the following data, solve for the degree of compaction. Field density test data: Weight of material taken from hole, kg. = Weight of sand to fill hole, kg. = Volume of hole, cu.m = 4.885 3.885 0.0028 Wet unit weight, kg/cu.m = Dry unit weight, kg/cu.m = 1745 1663 Laboratory Data: Maximum dry density, kg/cu.m. = Optimum Moisture Content, % = 2250 8.10 A BI - I

Problem 2: From the following data, solve for the degree of compaction. Field density test data: Weight of material taken from hole, kg. = Weight of sand to fill hole, kg. = Volume of hole, cu.m = 4.885 3.885 0.0028 Wet unit weight, kg/cu.m = Dry unit weight, kg/cu.m = 1745 1663 Laboratory Data: Maximum dry density, kg/cu.m. = Optimum Moisture Content, % = 2250 8.10 A BI - I

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter8: Stresses In A Soil Mass

Section: Chapter Questions

Problem 8.3P

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8 The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.24 kg Water content = 12.01% Max. dry unit weight from a laboratory compaction test = 19.70 kN/m3 Determine the relative compaction, in percent. Round off to two decimal places. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
Data for field density by sand cone method: Weight of bottle + cone + sand before going to the field = 8990.5 g Weight of soil excavated from hole = 7550 g Weight of bottle + cone + sand after use = 2931 g Weight of sand required to fill the cone, Wc = 1578 g Dry unit weight of sand = 1.533 g/cm3 Moisture content = 6% 1- Calculate dry unit weight of compaction in the field.
The following are results of a field unit weight determination test using sand cone method: Volume of hole = 0.0019 m3 Mass of moist soil from hole = 3.48 kg Water content = 12.43% Max. dry unit weight from a laboratory compaction test = 19.56 kN/m3 Determine the relative compaction, in percent. Hint: Relative compaction = Field dry unit weight / Max dry unit weight (lab)
The following results are obtained from standard compaction test for a soil, if Gs = 2.5 Water Content (%) 6.2 8.1 9.8 11.5 12.3 13.2 Unit weight (kN/m3) 16.9 18.7 19.5 20.5 20.4 20.1 Required: 1- The optimum water content (Wc %) 2- The maximum dry unit weight ( dry ) 3- The void ratio (e) 4- Degree of saturation (S %) 5- Find the weight of water needed to be added to 1 m3 to reach 100% saturation.
Explain the Effects of compaction procedure on dry density.
Determine the compaction effort of Standard Proctor Test in English unit Method A. (ft − lb/ft^3)
Refer to Problem 3.4. Using Eq. (3.22), determine the average relative density of sand.
For a silty clay soil given LL = 43 and PL = 18. Estimate the maximum dry unitweight of compaction that can be achieved by conducting a modified Proctor test. Use Eq attached.
A saturated soil sample has a unit weight of 19.24 KN/m3 and Gs = 2.70. Find Ydry, e, n,and w. 6 decimal places for the solution please
1.Three phases of a soil element? 2.Define volumetric relations (equation and text):e= , n=, S= 3. Define weight relations (equationand text):w=, Y= , Gs= 4. Range of values for degree of saturation? 5. Range of values for moisture content? 6. Correlation between dry unit weight and total unit weight (use w)? 7.Super equation (label each term)? 8. Unit weight of water ( English,metric)? 9. Average unit weight for medium dense sand? 10.Specific gravity for sand?
6. The relative compaction of a sand in the field is 93.5%. Given that dry unit weight max = 16.98 kN/m3 and dry unit weight min = 14.46 kN/m3. What is the dry unit weights in the field? (Ans: 15.88 kN/m3) What is the relative density compaction? (Ans: 60.1%) What is the water content of the sand if the moist unit weight is 18.42 kn/m3. (Ans: 16%)
7. The relative compaction of a sand in the field is 94%. Given that dry unit weight max = 16.2 kN/m3 and dry unit weight min = 14.9 kN/m3 . For the field conditions. What is the relative density compaction? (Ans: 27%) What is the dry unit weight? (Ans: 15.23 kN/m3) What is the moist unit weight at a moisture content of 10%? (Ans: 16.45 kN/m3 )