solution initial components A B с D H₂O H₂O H₂O, NaOH H₂O, NaOH initial type (check all that apply) acidic basic neutral acidic basic neutral acidic basic neutral acidic basic neutral change add KCI add HCl add NaCIO add HCIO effect of change on pH (check one) pH higher pH lower pH the same pH higher O pH lower pH the same pH higher pH lower pH the same pH higher pH lower pH the same
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- How to write the methodology? I have a practical of the MEASUREMENT USING PH METER, I don't know how to write the methodology. Here is the introduction: A pH meter is an electronic device mainly used for qualitative measurement, for thedetermination of acid and the basic value of a solution. Generally, it measures thehydrogen ion concentration/activity [H+] in a solution. It is denoted as:pH = - log10 [H+]In a pure water solution, the concentration of [H+] and [OH-] ions, respectively, rangefrom 1.0 x 10-1 M to 1.0 x 10-14 M. When [H+] is equal to [OH-] as when pure waterdissociates, the hydrogen ion concentration of pure water is equal to 1.0 x 10-7 M orpH = 7.00, defined as a neutral solution at 25°C, to be of temperaturedependent/endothermic dissociation.[H+] = [OH-] = 1.0 x 10-7 MWhen an ionic or polar substance is dissolved in water, it may change the relativenumbers of H+ and OH-. The higher the pH number, the lower the hydrogen ion concentration, and vice versa. Solution with an…Prepared buffer solution GivenAmmonia Volume = 68 mL | Ammonia Concentration = 0.17 MAmmonium Chloride Volume = 42 mL | Ammonium Chloride Concentration = 0.13 MDissociation Constant of Ammonia: 1.8x10-5What is the total vol. of bufferWhich of these apply to Image C (attached)? There should be 4 total answers: A. High End pH B. High Initial pH C. Vertical Line with Equivalence Point Tall D. Equivalence Point Not at pH 7 E. Equivalence point at pH 7 F. low end pH G. low initial pH H. Vertical Line with Equivalence Point Short Using the info identified above, what type of analyte and tirant combo are in the image. Options for Analyte and Titrant: - Weak base - Strong Acid - Strong Base - Weak Acid
- A titration system is set up as follows: the bottom flask contains a sample solution of 50.0-mL 0.50 M C2H3NH2 (ethylamine), the burette is filled with 0.20 M HCl as titrant. Kb of C2H3NH2 = 6.5 ´ 10-4 What is the initial pH of above sample solution before titration starts?Please answer it ALL ASAP and CORRECTLY for an upvote. PROVIDE YOUR FULL SOLUTION. You prepared a buffer solution by mixing 68 ml of 0.17 M ammonia and 42 ml of 0.13 M ammonium chloride. The dissociation constant of ammonia is 1.8x10^-5 What is the total volume of the buffer? What is the final concentration of the base? What is the final concentration of the salt? What is the acid strength of the solution? What is the pH of the buffer solution?A professor prepares a buffer solution that they need for the purification of protein from human cell lysates. They did mix weak acid and conjugate base and obtained the initial solution, which is characterised by these parameters. Final volume: 200mltotal buffer compound concentration: 150mMIntitial concentration weak acid: 0.03MInitial concentration conjugate base: 0.12MInitial pH 6.9buffer compound pka 6.3
- Consider a 0.10 M solution of a weak polyprotic acid (H2A) with the possible values of Ka1 and Ka2 given here.a. Ka1 = 1.0 * 10-4; Ka2 = 5.0 * 10-5b. Ka1 = 1.0 * 10-4; Ka2 = 1.0 * 10-5c. Ka1 = 1.0 * 10-4; Ka2 = 1.0 * 10-6Calculate the contributions to [H3O+] from each ionization step. At what point can the contribution of the second step be neglected?Which of these apply to the Image (attached)? There should be 4 total answers: A. High End pH B. High Initial pH C. Vertical Line with Equivalence Point Tall D. Equivalence Point Not at pH 7 E. Equivalence point at pH 7 F. low end pH G. low initial pH H. Vertical Line with Equivalence Point Short Using the info identified above, what type of analyte and tirant combo are in the image. Options for Analyte and Titrant: - Weak base - Strong Acid - Strong Base - Weak AcidThis is the reaction with Acid-Base indicator. Please explain clearly what the result below means. INDICATORS COLOR BLUE LITMUS PAPER TURNS RED RED LITMUS PAPER REMAINS RED CONGO RED RED/PINK PHENOLPHTHALEIN NO CHANGE
- In the experiment, we used titration to determine the total acid content ofsamples, which we reported in terms of molarity. Reporting acidity through pHmeasurements is quite different, in that we can only measure the amount of theacid in its ionized form. You were tasked to investigate a clear aqueous solutionof an unknown monoprotic acid. You decided to use two methods togather data.Method 1 – TITRATION: A 10. mL aliquot of the sample was diluted with 25 mLdistilled water. Two drops of phenolphthalein were added and then it was titrated3.54 mL of 0.048 M standardized NaOH to the endpoint.Method 2 – pH STRIP: You took 1 mL of the sample and used a pH strip toestimate the pH, which turned out to be around 3.3. Another 1 mL of the samplewas diluted with 9 mL of water. The pH was taken again and is now around 3.8.a) Calculate the molarity of the acid using the titration data.b) If we assume that the titrated unknown is a strong acid, predict thepH of the sample.c) Using pH strip results,…A student prepares a weak acid solution by dissolving 0.2400 g HZ to give 100. mL solution. The titration requires 30.0 mL of 0.1025 M NaOH. Calculate the molar mass of the acid. (a) Would the molar mass be too high, too low, or unaffected if the student accidentally used 0.1400 g in the calculation? Explain. ex. too high/too low/unaffected and directly proportional/inversely proportional/ unrelated (b) Would the molar mass be too high, too low, or unaffected if the student accidentally used 20.0 mL instead of 30.0 mL? Explain. ex. too high/too low/unaffected and directly proportional/inversely proportional/ unrelatedDetermine the [H3O+] of the eight buffer solutions made by mixing 1.10 M acetic acid and 0.900 M sodium acetate solutions according to the following volumes. The pKa for acetic acid, CH3CO2H (HAc), is 4.745. To enter exponential values, use the format 1.0e-5.