SOLVE -? Na₂ Co₂ + 2 Call₂ -> ? Cal 03 (5):.offilter paper = 0.00082.1547ieofСасоз =• Volume of Call used = 25.04 mL at 0.40MVolume of Na₂ CO₂ used = 40.00mL at 0-60Mto do is -massmassAll you meedCalculate24Limiting reactant%/ yield - ?% yield=?mass of CaCo3 madex 100%mass CaCO3 should have made↑based+ Nall1guponLR

Answered: Image /qna-images/answer/76d0ac32-ac67-48ad-8ad2-f9c2b3acc0b0.jpg

SOLVE - 2 ? Na₂ Co₂ + 2 Call₂ -> ? Cal 03 (s) + mass of 0.0008 g mass of Сасоз = Volume of Call used = 25.04 mL at 0-40M filter paper = All you need Calculate; Volume of Na₂CO3 used = 40.00 mL at 0.60M to do is - 2.1547 % yield = Limiting reactant %/ yield ? mass of CaCo3 madex 100% mass CaCO3 should have made 소 based upon - — Nall 2 LR

SOLVE - 2 ? Na₂ Co₂ + 2 Call₂ -> ? Cal 03 (s) + mass of 0.0008 g mass of Сасоз = Volume of Call used = 25.04 mL at 0-40M filter paper = All you need Calculate; Volume of Na₂CO3 used = 40.00 mL at 0.60M to do is - 2.1547 % yield = Limiting reactant %/ yield ? mass of CaCo3 madex 100% mass CaCO3 should have made 소 based upon - — Nall 2 LR

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.27QAP

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