Solve 6sin(π6x)=4 for the four smallest positive solutions x =

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A: given,

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A: In given figure∠P+∠R=180°3x+10+5x+10=1808x=180-20x=1608x=20

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A:

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A: We have to find Four smallest positive solution for- 4sin(π/2x)=3.....(1)

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A: The inverse rule of trigonometry states that, If sec(x)=y, then x = sec-1(y). Consider the given…

Q: Solve 4cos(5x)=2 for the smallest three positive solutions.

A: First solve for cos(5x)

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A:

Q: Solve for x: (4x+141)° (2x +27)° [A] 2 [B] 0 [C] 5 [D] 3

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A: Given,          sec2x-7=0

Q: Solve 6sin(π/2x)=4 for the four smallest positive solutions

A:

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A:

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A: The given two problems  are related to cyclic quadrilateral. Cyclic quadrilateral is a…

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A: Given,            2 cos2(x) -1 =0  and interval = [0, 2π)

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A: Given cosec2x+2=3cosec xWe know that cosec x=1sin xSo upon substituting we get:1sin2x+2=3sin x

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A: To solve the trigonometric equation.

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Q: Solve  5sin(π2x)=2 for the four smallest positive solutions x =

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Q: Solve 3sin(πx/2) = 2 for the four smallest positive solutions

A: We have to solve 3sin(πx/2) = 2 for the four smallest positive solutions

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Q: Solve 6cos(3x)=3 for the smallest positive solution

A: GIVEN , 6cos3x=3we have to solve for the smallest positive solution .

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Q: Solve your x. P(2x + 6)° (3x + 14)

A:

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A: Applying similarity of trangle

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Q: Solve for the value of x:  √2x+5 - √x+3=2

A: Given: