: Solve as indicated. Find the number k > 1 such that the region bounded by the curves y = 1, y = x-2, and x = k has area 6 square units. O Find the number k >0 such that the region bounded by the curves y = x2 and y = kx has area 9 square units. O Find the value of k such that the area of the region under the curve y = x(k – x), (0 <¤ < k), is 1 square unit. O Find the value of k such that the line y = kx bisects the region bounded by the x-axis and the curves y = x – x². - Find the value of k between -1 and 2 such that the area of the region bounded by the lines y = -x, y = 2x, and y = 1+ kx is a minimum. %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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d5

answer #5 pleaseeeee

: Solve as indicated.
Find the number k >1 such that the region bounded by the curves
y = 1, y = x¯2, and x = k has area 6 square units.
O Find the number k > 0 such that the region bounded by the curves
y = x? and y
kx has area 9 square units.
Find the value of k such that the area of the region under the curve
y = x(k – x), (0 < x < k), is 1 square unit.
|
Find the value of k such that the line y = kx bisects the region
bounded by the x-axis and the curves y = x – x².
Find the value of k between –1 and 2 such that the area of the region
bounded by the lines y = -x, y = 2x, and y = 1+ kx is a minimum.
-
%3D
Transcribed Image Text:: Solve as indicated. Find the number k >1 such that the region bounded by the curves y = 1, y = x¯2, and x = k has area 6 square units. O Find the number k > 0 such that the region bounded by the curves y = x? and y kx has area 9 square units. Find the value of k such that the area of the region under the curve y = x(k – x), (0 < x < k), is 1 square unit. | Find the value of k such that the line y = kx bisects the region bounded by the x-axis and the curves y = x – x². Find the value of k between –1 and 2 such that the area of the region bounded by the lines y = -x, y = 2x, and y = 1+ kx is a minimum. - %3D
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