Solve for Fv
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- Repeat Prob. 4.152 assuming that the 400-kN force is applied at O instead of L.The chain OA is 25 ft long and weighs 5 lb/ft. Find the maximum force in the chain and the distance H.A man on the wire singing "Man on a Wire" while practicing for his circus show has reached the center of the rope, creating a dip on the center angled at 63.2 degrees. If the mass of the man is 49.55 kg and the tension force that can be handled by the wire is 449.77N, would the wire break? Show the tension caused by the man hanging on the wire.
- If the maximum length of the spring is 40 cm, what average friction force opposes the motion of the mass?A man on the wire singing "Man on a Wire" while practicing for his circus show has reached the center of the rope, creating a dip on the center angled at 67.87 degrees. If the mass of the man is 42.23 kg and the tension force that can be handled by the wire is 301.26 N, would the wire break? Show the tension caused by the man hanging on the wire. (with illustration)find the height of a tree if the angle of its elevation of its top changes from 20° to 40° as the observer advances 23m toward its base. A. 158.5 m B. 138.5 m C. 159.5 m D. 148.5 m
- It is common to hang objects on doorknobs and over-the-door hooks. There is a limit to the amount of weight that a door can hold because of the forces exerted on the hinges. A door of height h = 2.5 m and width h/2 has a mass of M = 36 kg. The mass is distributed uniformly, so the center of mass is located at the geometric center of the door. One hinge is located a distance h/4 from the top of the door. The second hinge is a distance h/4 from the bottom of the door. Refer to (a) in the figure. The door’s weight is supported entirely by the two hinges and each hinge supports half of the weight. In other words, the vertical force exerted by each hinge is exactly one half of the total weight, including any additional load. For this problem, take the positive y-direction to be directly upward and the positive x-direction pointing from the hinge side of the door to the knob side. 1.) calculate the force, with its sign in Newtons that the upper hinge exerts on the door in the x axis.…A caisson for closing the entrance to a dry dock is of trapezoidal from 16 m wide at the top and 12 m wide at the bottom and 8 m deep. Find the total force in MN on the caisson if the water on the outside is 1 m below the top level of the caisson and the dock is empty. enclude your free body diagram. a.117.72 b.80.93 c.3.164 d.37.77the horizontal and vertical components of several forces are: (a) Ph = -200lb and Pv = 100lb : (b) Fh = 300lb and Fv = -200lb . determine each force and its angle with respect to the hozirontal (x-axis)
- To get up on the roof, a person (mass 85.0 kg) places a 6.20 m aluminum ladder (mass 15.0 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. The top of the ladder rests against a plastic rain gutter, which we can assume to be frictionless. The center of mass of the ladder is 2.00 m from the base, as measured along the ladder. The person is standing on the ladder 3.00 m from the base, as measured along the ladder. Find the normal reaction and friction forces (in N) on the ladder at its base. (Enter the magnitudes.)You place a 3.0-m -long board symmetrically across a 0.5-m -wide chair to seat three physics students at a party at your house. If 70-kg D sits on the left end of the board and 50-kg T on the right end of the board, where should 54-kg K sit to keep the board stable? Ignore the mass of the board and treat each student point- like objects. The positive z-direction is to the right, and the origin is at the center of the chair. (a)Determine the coordinate of the leftmost point on the board where K can sit to keep the board stable. (b)Determine the coordinate of the rightmost point on the board where K can sit to keep the board stable.You are pushing an80.0 N wheelbarrow as shown inFig. You lift upward on thehandle of the wheelbarrow so thatthe only point of contact betweenthe wheelbarrow and the groundis at the front wheel. Assume thedistances are as shown in the figure,where 0.50 m is the horizontaldistance from the center of thewheel to the center of gravity of thewheelbarrow. The center of gravityof the dirt in the wheelbarrow isassumed to also be a horizontal distanceof 0.50 m from the center of thewheel. Estimate the maximum totalupward force that you can apply to the wheelbarrow handles. (a) If youapply this estimated force, what is the maximum weight of dirt that youcan carry in the wheelbarrow? Express your answer in pounds. (b) If thedirt has the weight you calculated in part (a), what upward force does theground apply to the wheel of the wheelbarrow?