デジタル形式で段階的に解決ありがとう!!SOLVE STEP BY STEP IN DIGITAL FORMAT8. Four parallel forces act on a steel structural member.Determine the magnitudes of FA and FB such that the system can be reducedto a single force passing through point O.0.25 m0.05 m8 kNFA0.5 m20.4 myFB0.1 m10 kN0.15 m0.2 mX

FA is the force acting along the line of action of FA.FB is the force acting along the line of…

Answered: デジタル形式で段階的に解決ありがとう!! SOLVE STEP BY…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The mass of a solid hemisphere is measured once with a digital balance whose resolution is 1 g. The result is m = 50 g. With a caliper, the resolution of which is 0.05 mm, repeated measurements of the diameter D of the hemisphere are carried out. The values obtained for D: 100.30 mm; 100.00 mm; 100.60 mm; 100.10 mm; 100.25 mm; 100.50 mm; 100.40 mm; 100.20 mm; 100.30 mm; 100.35 mm. The result of measuring the mass m is: (a) (50 ± 1) g (b) (50.0 ± 0.58) g (c) (50.00 ± 0.58) g (d) (50.0 ± 0.5) g
P1=10KN P2=10KN P3=10KN
To measure the density of a stone, a digital scale and a beaker cup filled with water are used. The balance is used to measure the mass of the stone, while the beaker is used to measure the volume of the stone. It is known that the digital balance has a resolution of 0.1 g and that the beaker cup has a resolution of 5 ml. Repeated mass measurements return the following values: 250.0 g; 249.9 g; 250.3 g; 249.6g; 250.1 g; 249.7g; 250.4 g; 250.0 g; 248.8 g; 250.2 g The volume is measured only once. Placing the stone in the beaker, a volume of displaced water equal to 50 ml is measured. Using a k=2.5, check if the density of the stone is compatible or out of line with the value ρ = (4910 ± 65) kg.m-3 (a) none of the above (b) the values are compatible (c) missing data to perform the compatibility test (d) the values are discrepant
1. A double-acting air compressor has 18 x 12 inches, 626 rpm. Determine the volume displacement in ft^3/min 2. An air compressor piston displacement is 6,308 cm^3/min when operates at 964 rpm and volumetric efficiency of 75 %. Determine the capacity of air compressor in cm^3 per min.
Vibration Engineering: Mass = 10 kilogramsSpring constant = 400 Newtons per meterPeriodic Force = 6 KilonewtonsForcing Frequency = 5 radians per secondDamping coefficient = 200 Newton second per meter Calculate: (Express the final answer in 4 significant digits) -the phase angle in radians -the natural frequency in radians per second -the amplitude of steady-state vibration in meters
given:Q2A=12 INCHESAB= 2FT 4 INCHESBC= 8 INCHESDE = 1 FT 3 INCHESQ7E= 12 INCHESQ5C= 2 FTDF= 2 FTCE = 3FT Ks -> use appropriate scaleKv -> 400ft/min= 1 inchVa= 472 ft/ min ☆ Solve the velocities of F and E by Resolution and Composition☆ pls show the output
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66. Subject:- Mechanical Enginreering
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1. A double-acting air compressor has 18 x 12 inches, 626 rpm. Determine the volume displacement in ft^3/min Answer in whole number 2. An air compressor piston displacement is 6,308 cm^3/min when operates at 964 rpm and volumetric efficiency of 75 %. Determine the capacity of air compressor in cm^3 per min.
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ᴀ ꜱᴏʟɪᴅ ꜱʜᴀꜰᴛ 2.51" ɪɴ ᴅɪᴀᴍᴇᴛᴇʀ ᴛʀᴀɴꜱᴍɪᴛꜱ ᴀɴ ᴀʟᴍᴏꜱᴛ ᴄᴏɴꜱᴛᴀɴᴛ ᴘᴏᴡᴇʀ ᴏꜰ 100 ʜᴘ ᴀᴛ ᴀ ᴄᴏɴᴛɪɴᴜᴏᴜꜱʟʏ ᴠᴀʀʏɪɴɢ ꜱᴘᴇᴇᴅ ᴏꜰ 100 ᴛᴏ 500 ʀᴘᴍ. ᴄᴏᴍᴘᴜᴛᴇ ᴛʜᴇ ᴍᴇᴀɴ ꜱᴛʀᴇꜱꜱ ᴄᴏᴍᴘᴏɴᴇɴᴛ (SMs) ᴏꜰ ᴛʜᴇ ꜱʜᴀꜰᴛ ɪɴ ᴘꜱɪ. ᴇxᴘʀᴇꜱꜱ ʏᴏᴜʀ ᴀɴꜱᴡᴇʀ ᴜꜱɪɴɢ 4 ꜱɪɢɴɪꜰɪᴄᴀɴᴛ ꜰɪɢᴜʀᴇꜱ. ʀᴏᴜɴᴅ ʏᴏᴜʀ ᴀɴꜱᴡᴇʀ ᴛᴏ 4 ꜱɪɢɴɪꜰɪᴄᴀɴᴛ ꜰɪɢᴜʀᴇꜱ.

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