Solve the following system of differential equations: r(t) = 4x₁(t) = x₂(t); x₂(t) = − x₁(t) + 3x2(t) + x3(t); x3 (t) = 3x₁ (t) — 2x2(t) + 2x3(t). with initial conditions x₁(0) = x₂(0) = x3 (0) = 1.

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