Question
Asked Oct 5, 2019
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Solve the given boundary-value problem.
y'' − 2y' + 2y = 2x − 2,  y(0) = 0, y(π) = π
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Expert Answer

Step 1

Find the homogeneous solution of the given IVP as follows.

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The given BVP is as follows, -2y2y2x-2, y(0)= 0, y(z)=7 Consider the homogeneous part y 2y'+2y 0 The characteristi ce equation is m2 - 2m+ 2 0. m2 - 2m+2 = 0 2+/4-8 2 2+-4 2 2+2i 2 1- i,1+ i The homogeneous solution is y e* (C cosx+ C2 sinx)

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Step 2

Find the particular solution of ...

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The BVP is y" 2y'+2y 2x-2, y(0) = 0, y(7)=T. Let the particular solution be of the form, y, = Ax +B 02.4 2(Ax+ B)= 2x- 2 24 2 and -24+2B -2 A 1 and 2B =-2+2 A 1 and B = 0 The particular solution is yp = = x.

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