solve with Matlab Assignment vs. Equals is important in loops. An assignment is a - b and means assign value b to variable a. The equals operator is ab results in 1 or yes if they are equal, 0 or no if they are not. The final type of loop is a WHILE loop. It requires that a series of operations occur while the condition applied to a specified variable is correct. The example syntax is: i-10; while i>5 end Practice Problem: Given the matrix: M-[1 1; 1 3:]; Use loops to determine how many of the entries are greater than 1 and the location of all qualifying entries (the corresponding row and column).

solve with Matlab Assignment vs. Equals is important in loops. An assignment is a - b and means assign value b to variable a. The equals operator is ab results in 1 or yes if they are equal, 0 or no if they are not. The final type of loop is a WHILE loop. It requires that a series of operations occur while the condition applied to a specified variable is correct. The example syntax is: i-10; while i>5 end Practice Problem: Given the matrix: M-[1 1; 1 3:]; Use loops to determine how many of the entries are greater than 1 and the location of all qualifying entries (the corresponding row and column).

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please explain Crime Wave more clearly for me please there's a picture of the decription and also please comment on each line if possible on the code below to for me to have a better understanding of what each line is doing. It is in C++. Please also give the space and time complexity and the reason why. #include <stdio.h>#include <string.h>#include <math.h>#define eps 1e-6double W[105][105];int N, M;int mx[105], my[105]; // match arrdouble lx[105], ly[105]; // label arrint x[105], y[105]; // used arrint hungary(int nd) { int i; x[nd] = 1; for(i = 1; i <= M; i++) { if(y[i] == 0 && fabs(W[nd][i]-lx[nd]-ly[i]) < eps) { y[i] = 1; if(my[i] == 0 || hungary(my[i])) { my[i] = nd; return 1; } } } return 0;}double KM() { int i, j, k; double d; memset(mx, 0, sizeof(mx)); memset(my, 0, sizeof(my)); memset(lx, 0, sizeof(lx)); memset(ly, 0, sizeof(ly));…
In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83, 65, 85]} write your own describe function that produces thesame 8 statistical results, for each one of the columns, that the built-in describe() function does.Note 1: Use the sample standard deviation formula (that is, the denominator is: N-1)Note 2: Your algorithm should work for any number of columns not just for 5Note 3: You can use the np.percentile() for the 25% and 75% percentile as well as the sort()built-in functions
In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83,65,85]} Write your own describe function that produces the same 8 statistical results, for each one of the columns, that the built-in describe() function does. Note 1: Use the sample standard deviation formula (that is, the denominator is: N-1) Note 2: Your algorithm should work for any number of columns not just for 5 Note 3: You can use the np.percentile() for the 25% and 75% percentile as well as the sort() built-in functions
Consider the following procedure: procedure mystery (x, y, z); integer x, y, z;beginz = 2; y= z+x;endand consider the following code fragment: A[1] := 2;A[2] := 1;n := 1;mystery (A[1],A[n],n); What will be the final values of n, A[1] and A[2] if the parameters are passed by reference?
Correct answer will be upvoted else downvoted. Computer science. Presently Nezzar has a beatmap of n particular focuses A1,A2,… ,An. Nezzar might want to reorder these n focuses so the subsequent beatmap is great. Officially, you are needed to find a change p1,p2,… ,pn of integers from 1 to n, to such an extent that beatmap Ap1,Ap2,… ,Apn is great. In case it is unthinkable, you ought to decide it. Input The primary line contains a solitary integer n (3≤n≤5000). Then, at that point, n lines follow, I-th of them contains two integers xi, yi (−109≤xi,yi≤109) — directions of point Ai. It is ensured that all focuses are unmistakable. Output In case there is no arrangement, print −1. In any case, print n integers, addressing a legitimate change p. In case there are numerous potential replies, you can print any.
Implement Thirsty problem using semaphore. Write the code in C/C++ Scenario: To drink, a thirsty person must have three things; water, ice and a glass. There are three thirsty people, each having a different one (and only one) of the three required items. A fourth person, a server has unlimited supply of all three items. If nobody is drinking, the server places two of the three items (chosen at random) onto table. Thirsty person who can make a drink from those two items will pick them up and drink a glass of ice water. When done, thirsty person will notify the server and the process will repeat.
Consider the following procedure: procedure mystery (x, y, z); integer x, y, z;beginz = 2; y= z+x;endand consider the following code fragment: A[1] := 2;A[2] := 1;n := 1;mystery (A[1],A[n],n); What will be the final values of n, A[1] and A[2] if the parameters are passed by name?
Consider the following procedure: procedure mystery (x, y, z); integer x, y, z;beginz = 2; y= z+x;endand consider the following code fragment: A[1] := 2;A[2] := 1;n := 1;mystery (A[1],A[n],n); What will be the final values of n, A[1] and A[2] if the parameters are passed by value?
Please write a python program with explanation data structure& algorithm and time &space complexity Given a list of [personName, accessTime], for each person, return the earliest 1-hour interval in which he has swipe badges 3 or more times, e.g.[A, 0], [A, 5], [A, 59], [A, 60] ,[A, 61]return [A, 0], [A, 5], [A, 59], [A, 60] not [A, 5], [A, 59], [A, 60] ,[A, 61]
This assignment does not exactly match the one in the textbook on which it is based. I don't want any counter-controlled loops in your solution. Your solution should be able to detect when the accuracy isn't improving and then display the results of the work (as outlined below): Look at Programming Exercise **5.25 in the textbook on approximating the value of π. It is described as: π = 4 ( 1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 + ... + (-1)^(i+1)/(2i-1) ) Notice that Java has the best possible value of π that can be stored as a type double available as Math.PI (part of the java.lang package). See how close you can get to the best value of π using a loop with the above technique. Notice that the above implies you are testing the value of your own estimate as it approaches the best value available in Java (as a type double). This would not be a pre-determined, counter-controlled loop. You are testing the results (sentinel-controlled) until you reach a value with the minimum discrepancy…
Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n2) and runtime should be under 1 second. Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Output FormatFor each query, output one line containing an integer Dn. The number must be output mod (109 + 7). Sample Input 0:501234 Sample Output 0:10129 Edge Case: (to test against runtime and timeout error)300000 (number of queries)300000300000300000300000...and so on until there are 300,000 of them The actual code: def solve(n): MOD = 1000000007 # compute and return answer here q = int(input().rstrip()) outs = [] for i in range(q): n = int(input().rstrip()) outs.append(solve(n)) print("{}".format("\n".join(list(map(str,outs)))))
Write a program that simulates flipping a coin to make decisions. The input is how many decisions are needed, and the output is either heads or tails. Assume the input is a value greater than 0. Ex: If the input is: 3 the output is: headstailsheads For reproducibility needed for auto-grading, seed the program with a value of 2. In a real program, you would seed with the current time. In that case, every program's output would be different, which is what is desired but can't be auto-graded. Note: A common student mistake is to call srand() before each call to rand(). But seeding should only be done once, at the start of the program, after which rand() can be called any number of times. Your program must define and call the following function that randomly picks 0 or 1 and returns "heads" or "tails". Assume the value 0 represents "heads" and 1 represents "tails".string HeadsOrTails() #include <iostream>#include <cstdlib>using namespace std; /* Define your function here */…