Something is wrong Merge-Sort... Recall the following pseudo-code of Merge-Sort, which is supposed to sort A[p...r] correctly. You don't need to show intermediate steps,but they could help you get some partial points if your final solution is wrong.MERGE-SORT(A, p,r)1 if p

MergeSort(arr[], l, r) If r > l 1. Find the middle point to divide the array into two…

Answered: Something is wrong Merge-Sort... Recall…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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You are running radix sort (base 10) on values 123, 322, 311, 332, 312, 132, 213, 321, 323. Unfortunately, the counting-sort implementation that your radix-sort calls is "anti-stable", that is, in case of a tie, it always reverses the order of two keys. What is the final order you get? Show the array after each pass.
Dr. Sponge thinks it's too hard to implement Merge. So, he wants to replace Merge with Insertion Sort (yes, the insertion sort you learned in class). The following is the pseudo-code of the new Merge-Sort, Merge-Sort(p, r) 1. if p == r return 2. q = floor of (p+ r) / 2 3. Merge-Sort(p, q) 4. Merge-Sort(q+1, r) 5. Insertion-Sort(p, r) Give the recurrence for the running time of this new Merge-Sort and solve it. We let T(n) denote the running time when input array has n elements. By solving the recurrence (no need to show how you solved it), we obtain T(n) =
I need help in understanding the Partition of the Merge sort using an array of number
Modify the FindBestPlan(S) function to create a function FindBestPlan(S, O),where O is a desired sort order for S, and which considers interesting sortorders. A null order indicates that the order is not relevant. Hints: An algorithmA may give the desired order O; if not a sort operation may need to be added to get the desired order. If A is a merge-join, FindBestPlan must be invoked on the two inputs with the desired orders for the inputs.
The following is the pseudo-code for merge-sort algorithm: MERGE-SORT(A,p,r) if p < r q = [(p + r)/2] MERGE-SORT(A, p, q) MERGE-SORT(A,q + 1,r)MERGE(A, p, q, r) What is the T(n) expression for this algorithm?
Write an in-place merge sort algorithm that does not require a temporary array to merge the two halves. What is the efficiency of your solution?
Apply Merge sort and Quick to sort the list, U , N , I , V, E, R, S, I, T, Y in alphabeticalorder. (hand written please)
SO You have been given two integer arrays/lists (ARR1 and ARR2) of size N and M, respectively. You need to print their intersection; An intersection for this problem can be defined when both the arrays/lists contain a particular value or to put it in other words, when there is a common value that exists in both the arrays/lists.Note :Input arrays/lists can contain duplicate elements.The intersection elements printed would be in the order they appear in the first sorted array/list (ARR1).Input format :The first line of input contains an integer 'N' representing the size of the first array/list.The second line contains 'N' single space separated integers representing the elements of the first the array/list.The third line contains an integer 'M' representing the size of the second array/list.The fourth line contains 'M' single space separated integers representing the elements of the second array/list.Output format :Print the intersection elements. Each element is printed in a separate…
show example on implementing Merge sort and Quick sort
The running time of Merge, which is part of Merge Sort, is O(
Q: Modify the following algorithm of Merge Sort in such a way that during every recursive call it should divide the array into three partitions instead of two. What will be effect of this modification on the running time of Merge Time? Merge-Sort (A, left, right) if left ≥ right return else middle ← (left+right)/2 Merge-Sort(A, left, middle) Merge-Sort(A, middle+1, right) Merge(A, left, middle, right) Merge(A, left, middle, right) n1 ← middle – left + 1 n2 ← right – middle create array L[n1], R[n2] for i ← 0 to n1-1 do L[i] ← A[left +i] for j ← 0 to n2-1 do R[j] ← A[middle+j] k ← i ← j ← 0 while i< n1 & j< n2 if L[i] < R[j] A[k++] ← L[i++] else A[k++] ← R[j++] while i< n1 A[k++] ← L[i++] while j < n2 A[k++] ← R[j++]
True or false: In-place merge sort is a stable sort.

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Something is wrong Merge-Sort... Recall the following pseudo-code of Merge- Sort, which is supposed to sort A[p..r] correctly. You don't need to show intermediate steps, but they could help you get some partial points if your final solution is wrong. MERGE-SORT(A, p,r) 1 if p