speople working (x) 0.671 0.319 To test the hypotheses Ho:B1-0 versus HA: B1 *0, the P-value of the test, based on the compoted t-Stat value, is: 0.0655 O 0.0671 0.0687
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- Question #4. US Universities found that 72% of people are concerned about the possibility that their personal records could be stolen over the Internet. If a random sample of 300 college students at a Midwestern university were taken and 228 of them were concerned about the possibility that their personal records could be stolen over the Internet, could you conclude at the 0.025 level of significance that a higher proportion of the university's college students are concerned about Internet theft than the public at large? Report the p-value for this test. Z0.025 = 1.96QUESTION 5 PART A- Carry out a formal t-test for the association between extroversion and neuroticism in personalities. H0: The population correlation coefficient is 0. HA: The population correlation coefficient is not 0. What is the critical value of the t-statistic required to reject the null hypothesis at a confidence level of 0.05? (Report the absolute value. The t-distribution is symmetric, thus it is easier to compare the absolute value of the t-statistic with the positive values in statistical table C). QUESTION 5 PART B- The data in chocolate_nobels is not bivariate normal. Plot a scatter plot of the data. Based on the scatter plot, how does the data deviate from bivariate normality? There are outliers The standard deviation of both variables seems to increase as the variables increase. The relationship between the two variables is not linear. The standard deviation of the Nobel prize winners seems to increase as chocolate…Question 21 A quality-assurance inspector periodically examines the output of a machine to determine whether it is properly adjusted. When set properly, the machine produces nails having a mean length of 2.000 inches, with a standard deviation of 0.070 inches. For a sample of 35 nails, the mean length is 2.025 inches. If the null and alternative hypotheses can be used to conclude that the machine is adjusted properly, at 15% level of significance, do you reject or fail reject H0? Reject H0 because Z-statistic is greater than z-critical Reject H0 because Z-critical is more than 1.435 Reject H0 because Z-critical is less than -1.435 Reject H0 because Z-critical lies between 1.435 and -1.435
- Question 18 A quality-assurance inspector periodically examines the output of a machine to determine whether it is properly adjusted. When set properly, the machine produces nails having a mean length of 2.000 inches, with a standard deviation of 0.070 inches. For a sample of 35 nails, the mean length is 2.025 inches. If the null and alternative hypotheses can be used to conclude that the machine is adjusted properly, at 15% level of significance, what is your conclusion? There is enough evidence to support the claim There is no enough evidence to support the claim There is enough evidence to reject the claim There is no enough evidence to reject the claimQuestion 8 A quality-assurance inspector periodically examines the output of a machine to determine whether it is properly adjusted. When set properly, the machine produces nails having a mean length of 2.000 inches, with a standard deviation of 0.070 inches. For a sample of 35 nails, the mean length is 2.025 inches. if the null and alternative hypotheses can be used to conclude that the machine is adjusted properly. Compute the value of the test statistic. 2.1128 2.1129 2.1130 2.1131Question 11 The null and alternative hypotheses for a population proportion, as well as the sample results, are given. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: H0:p=0.5 vs Ha:p<0.5;Sample data: p^=38100=0.38 with n=100 Round the p-value to three decimal places. p-value =Enter your answer in accordance to the question statement
- Question # 19. With individual lines at its various windows, a post office finds that the standard deviation for waiting times for customers on Friday afternoon is 7.2 minutes. The post office experiments with a single, main waiting line and finds that for a random sample of 25 customers, the waiting times for customers have a standard deviation of 3.5 minutes on a Friday afternoon. With a significance level of 5%, test the claim that a single line causes lower variation among waiting times for customersQuestion 2. A random sample of 22 values was selected from a population and the sample standarddeviation was computed to be 340. Based on this sample result, compute a 90% confidenceinterval estimate for the true population standard deviation. Question 3. Two samples of sizes 15 and 16 are drawn from two normally distributed populations havingmeans of 16 and 11, respectively. If the sample variances are 6 and 5, determine whether the firstsample has significantly lower variance than the second sample at 0.025 significance levelQuestion 02 There is a claim that drink driving has been very common in high ways. The Highway Police randomly caught 300 drivers for breath alcohol test and found that 14% of drivers have breath alcohol over the legal limit. At 4% level of significance, use the p-value approach to test the hypothesis that the percentage of drivers who are drink driving is more than 10%.
- Do types of crimes reported on television newscasts differ by the age of the criminals? A researcher uses her dvr to record the local television news for a 2-week period of time. She records the types of crimes and notes the age of the offender. Conduct a chi-square test (alpha = .05) of the null hypothesis that televised offense type does not vary by age group of offender. Offense type Young middle age older violent 27 10 3 property 14 12 11 sex 7 9 5 Report the obtained chi-square, df, and critical chi-square. Report your findings based on the null hypothesis.QUESTION 5 Two different hardening processes, namely saltwater quenching and oil quenching are used onsamples of a particular type of metal alloy. The hardness (in N/mn2) results are shown in Table 4.Assume that hardness is normally distributed. Calculate the 98% confidence interval for the ratioof two population variances for two different hardening processes saltwater quenching and oilquenching. Interpret the result. Table 4Saltwater Quenching Oil Quenching145 152150 150153 147148 155141 140152 146146 158154 152139 151148 143Question 2 The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution.Test H0 : p1=p2 vs Ha : p1<p2 when the samples have n1=170 with p^1=0.17, and n2=80 with p^2=0.23. The standard error of p^1-p^2 from the randomization distribution is 0.06.Find the value of the standardized z-test statistic.Round your answer to two decimal places.z= Enter your answer in accordance to the question statement