Standard solution : 0.201 grams of acetylsalicylic acid was combined with 10 mL of 0.5 M NaOH, then transfered to a 100 mL flask and filled the rest of the way with water Then 0.500 mLs of the standard solution was transfered to a 10.00 mL flask and diluted to the 10 mL mark with 0.02 M of buffered iron chloride. Number of moles of NaOH = 0.005 moles Since the reaction between acetylsalicylic acid and NaOH is a 1:1 reaction, the number of moles of acetylsalicylic acid used in the reaction is also 0.005 moles. the concentration from analysis question 5: acetylsalicylic acid in the 100.00 mL volumetric flask is 0.050 M. From your plot, what is the value of εb? From the Beer- Lambert law For the aspirin sample, calculate the concentration of acetylsalicylic acid present using the value of εb that you found The concentration from analysis question 5 represents the concentration in the 10.00 mL sample that was prepared in the volumetric flask using an aliquot of the solution in the 100.00 mL volumetric flask. Calculate the concentration of acetylsalicylic acid in the 100.00 mL volumetric flask.
Standard solution : 0.201 grams of acetylsalicylic acid was combined with 10 mL of 0.5 M NaOH, then transfered to a 100 mL flask and filled the rest of the way with water Then 0.500 mLs of the standard solution was transfered to a 10.00 mL flask and diluted to the 10 mL mark with 0.02 M of buffered iron chloride. Number of moles of NaOH = 0.005 moles Since the reaction between acetylsalicylic acid and NaOH is a 1:1 reaction, the number of moles of acetylsalicylic acid used in the reaction is also 0.005 moles. the concentration from analysis question 5: acetylsalicylic acid in the 100.00 mL volumetric flask is 0.050 M. From your plot, what is the value of εb? From the Beer- Lambert law For the aspirin sample, calculate the concentration of acetylsalicylic acid present using the value of εb that you found The concentration from analysis question 5 represents the concentration in the 10.00 mL sample that was prepared in the volumetric flask using an aliquot of the solution in the 100.00 mL volumetric flask. Calculate the concentration of acetylsalicylic acid in the 100.00 mL volumetric flask.
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter7: Components Of Optical Instruments
Section: Chapter Questions
Problem 7.10QAP
Related questions
Question
Standard solution : 0.201 grams of acetylsalicylic acid was combined with 10 mL of 0.5 M NaOH, then transfered to a 100 mL flask and filled the rest of the way with water
Then 0.500 mLs of the standard solution was transfered to a 10.00 mL flask and diluted to the 10 mL mark with 0.02 M of buffered iron chloride.
Number of moles of NaOH = 0.005 moles
Since the reaction between acetylsalicylic acid and NaOH is a 1:1 reaction, the number of moles of acetylsalicylic acid used in the reaction is also 0.005 moles.
the concentration from analysis question 5: acetylsalicylic acid in the 100.00 mL volumetric flask is 0.050 M.
- From your plot, what is the value of εb? From the Beer- Lambert law
- For the aspirin sample, calculate the concentration of acetylsalicylic acid present using the value of εb that you found
- The concentration from analysis question 5 represents the concentration in the 10.00 mL sample that was prepared in the volumetric flask using an aliquot of the solution in the 100.00 mL volumetric flask. Calculate the concentration of acetylsalicylic acid in the 100.00 mL volumetric flask.
Transcribed Image Text:Absorbance
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
Plot of Concentration vs Absorbance
y = 350.5x + 0.075
R² = 0.9732
0.0005
0.001
0.0015
Concentration (M)
0.002
0.0025
Transcribed Image Text:Mass of Acetylsalicylic
Acid
Solution
Solution #1
Solution #2
Solution #3
Solution #4
Solution #5
Sample Solution
Value Unit
0.201 g
Absorbance
0.770
0.610
0.523
0.402
0.173
0.745
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