Starting with solid glycine-HCl and 0.75 M NaOH, how would you prepare 500 mL of 0.050 M glycine buffer with a pH = 9.90? (pKa1 = 2.35, pKa2 = 9.78, glycine-HCl = HOOC–CH2–NH3+ Cl– MW = 111.5) What would be the change in pH upon addition of 2 mL of 0.1 M HCl solution on 10 mL of the buffer in #1?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
Problem 119QRT
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Starting with solid glycine-HCl and 0.75 M NaOH, how would you prepare 500 mL of 0.050 M glycine buffer with a pH = 9.90? (pKa1 = 2.35, pKa2 = 9.78, glycine-HCl = HOOC–CH2–NH3+ Cl– MW = 111.5) What would be the change in pH upon addition of 2 mL of 0.1 M HCl solution on 10 mL of the buffer in #1?
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