State the null and alternative hypotheses. O Hoi Hs0°c = H60°c = H70°C Hgi Hs0oc * H60°C * H70°C O Hoi Hs0°c * Ho0°c * H70°C Hgi Hso°c = H60°c = H70°C Not all the population means are equal. O Hoi Hgi Hs0°c = H60°c = H70°C O Hoi Hsooc = H60°c = H70°c_ H3: Not all the population means are equal. O Ho: At least two of the population means are equal. H3: At least two of the population means are different. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Do not reject Ho. There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal. Reject Ho. There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal. Reject Ho. There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal. Do not reject Ho. There is not sufficient evidence to conclude that the mean vields for the three temperatures are not equal.

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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Question
Source
Sum
Mean
Degrees
of Freedom
F
p-value
of Variation
of Squares
Square
Treatments
Error
Total
Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process.
State the null and alternative hypotheses.
O Ho: H50°c = Hoo°c = H70°C
H3: H50°c # H60°c * H70°C
O Ho: H50°c # Ho0°c H70°C
H3: H50°c = H60°c = 470°C
O H: Not all the population means are equal.
Ha: H50°c = H60°c = 470°C
O Ho: H50°c = Ho0°c = H70°C
H: Not all the population means are equal.
O Ho: At least two of the population means are equal.
H: At least two of the population means are different.
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
O Do not reject Ho. There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal.
O Reject Ho. There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal.
O Reject Ho. There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal.
O Do not reject Ho. There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal.
Transcribed Image Text:Source Sum Mean Degrees of Freedom F p-value of Variation of Squares Square Treatments Error Total Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process. State the null and alternative hypotheses. O Ho: H50°c = Hoo°c = H70°C H3: H50°c # H60°c * H70°C O Ho: H50°c # Ho0°c H70°C H3: H50°c = H60°c = 470°C O H: Not all the population means are equal. Ha: H50°c = H60°c = 470°C O Ho: H50°c = Ho0°c = H70°C H: Not all the population means are equal. O Ho: At least two of the population means are equal. H: At least two of the population means are different. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Do not reject Ho. There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal. O Reject Ho. There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal. O Reject Ho. There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal.
To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow.
Temperature
50°C
60°C
70°C
35
30
22
25
31
27
37
35
28
40
23
31
28
21
37
Construct an analysis of variance table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Source
Sum
Degrees
of Freedom
Mean
F
p-value
of Variation
of Squares
Square
Treatments
Error
Total
Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process.
Transcribed Image Text:To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 35 30 22 25 31 27 37 35 28 40 23 31 28 21 37 Construct an analysis of variance table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean F p-value of Variation of Squares Square Treatments Error Total Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process.
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