Station Station Distance (m) Adjusted interior angle 103°22' 102°57' | 103° 9' 30"|-0°19'12" | 102° 50' 18" Observed interior angle correction OcC obs Direct Reversed Мean A 11.55 В 13.20 B A 13.20 88°14' 88°14' 88° 14' -0°19'12" 87° 54' 48" 17.42 113°36' 112°48' 113° 12' -0°19'12" | 112° 52 '48" B 17.42 D 10.00 D 10.00 156°06' 154°31' 155° 18' 30" | -0°19'12" | 154° 59' 18" E 13.90 E D 13.90 81°42' 81°42' 81° 42' -0°19'12" 81° 22' 48" A 11.55 Length, Calculated LATITUDE Bearing DEPARTURE LINE m +N -S +E -W AB BC CD DE EA Adjusted LATITUDE Adjusted DEPARTURE Double LINE DMD -S +E -W Area 2A АВ ВС CD DE EA

Station Station Distance (m) Adjusted interior angle 103°22' 102°57' | 103° 9' 30"|-0°19'12" | 102° 50' 18" Observed interior angle correction OcC obs Direct Reversed Мean A 11.55 В 13.20 B A 13.20 88°14' 88°14' 88° 14' -0°19'12" 87° 54' 48" 17.42 113°36' 112°48' 113° 12' -0°19'12" | 112° 52 '48" B 17.42 D 10.00 D 10.00 156°06' 154°31' 155° 18' 30" | -0°19'12" | 154° 59' 18" E 13.90 E D 13.90 81°42' 81°42' 81° 42' -0°19'12" 81° 22' 48" A 11.55 Length, Calculated LATITUDE Bearing DEPARTURE LINE m +N -S +E -W AB BC CD DE EA Adjusted LATITUDE Adjusted DEPARTURE Double LINE DMD -S +E -W Area 2A АВ ВС CD DE EA

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Compute for the coordinates of station O. Note that: A has a northing of 1620925.334 and easting of 507672.847. B has a northing of 1620923.996 and easting of 507617.614. C has a northing of 1620694.527 and easting of 507681.770. STATION OCCUPIED STATION OBSERVED HORIZONTAL ANGLE (m) O B 0˚00’00” A 0˚29’49” O A 0˚00’00” C 64˚08’18”
ANSWER KEY: D= 51.8319m∆h= 13.5430mElev Sta. A= 70.8530m
The following data were obtained by stadia observation: vertical angle, +12deg 30 min; upper stadia hair reading and lower stadia hair readings, 4.500 and 3.250m, respectively. The rod reading was taken at 3.875m above the stadia point at A and the height of instrument above the instrument station, B, is 1.620m. If the stadia interval factor is 99.5 and the instrument constant is 0.381m, compute the horizontal distance between theinstrument stationand the stadia point. Compute also the difference in elevation between the two ground points.
The following data were obtained by stadia observation: vertical angle, + 12deg 51 min; upper and lower stadia hair reading, 4.311 and 3.730 m, respectively. the rod reading was taken at 3.785m above the stadia point A and the height of instrument set up at point B is 1.620m. If the stadia interval factor is 99.5 and the stadia constant is 0.381m, what is the vertical distance? a.54.098 b.94.780 c.12.620 d.26.364
There are two points, A and B: elevations above datum are hA=1760ft and hB=1425ft Images a and b on a vertical photograph have photo coordinates xa=2.95in., ya=2.32in., xb=−1.64in., and yb=−2.66in. The camera focal length was 152.4mm and the flying height above datum 7700ft. An image c of a third point C appears. Its elevation hC=1455ft and its photo coordinates are xc=3.20in. and yc=−2.66in Using EXCEL Calculate Angle A Calculate Angle B Calculate Angle C
A line of three wire differential levels goes from benchmark Gloria to benchmark Carey. The length of the line was determined to be 1487 m. The instrument had a stated compensator accuracy of ± 1.5 mm/km. The instrument-rod combination had an estimated reading error of ±0.2 mm per 40 m. Sight distances were consistently kept to approximately 50 ± 5 m. If the observed difference in the elevation in 23.4516m, what is the estimated error in the final elevation difference?
The interior angles of a hexagon were observed and recorded as follows:A=122º31’02”, B=123º26’17”, C=130º05’07”, D=120º15’47”, E=160º50’35” and F=62º53’07”. The discrepancy of the measurement is?
The following data were obtained by stadia observation: vertical angle, + 12deg 51 min; upper and lower stadia hair reading, 4.311 and 3.730 m, respectively. the rod reading was taken at 3.785m above the stadia point A and the height of instrument set up at point B is 1.620m. If the stadia interval factor is 99.5 and the stadia constant is 0.381m, what is the difference in elevation? a.10.455 b.24.109 c.20.852 d.34.321
Given:Upper reading = 1.64 mMiddle reading = 1.57 mLower reading = 1.51 mVertical Middle Angle = 10°32’00”Elev of point A = 333 mH of instrument = 1.2 mK = 100Stadia Constant = 0 Solve the ff.: A. Inclined, horizontal, and vertical distance B. Elevation of point B.
Surveying Question: A differential leveling circuit starts at benchmark Concrete Benchmark (Elevation=232.051m) goes out to an unknown benchmark and then continues to a known control point (Elevation=227.975m). Two turning points are used with the measurements included in the attached table. Determine the elevation of the unknown benchmark Determine the order and class of the survey. For First order Class 1: Allowable Error= +/- 4(K)1/2 Range of Constant= m less than/equal to 4 For First Order Class 2: Allowable error= +/- 5(K)1/2 Range of constant= m greater than/equal to 4, and m less than equal to 5 (between 4 and 5) For Second Order Class 1: Allowable error = +/- 6(K)1/2 Range of Constant = m greater than/equal to 5, and m less than equal to 6 (between 5 and 6) For Second Order Class 2: Allowable error = +/- 8(K)1/2 Range of Constant = m greater than/equal to 6, and m less than equal to 8 (between 6 and 8) For Third Order, Any Class: Allowable Error = +/-12(K)1/2 Range…
ANSWER KEY: PROBLEM 5.10K1=102.2495mPROBLEM 5.11 D=150.7275m∆h= 33.8483m
Answer Keys: By = 49,111.11 N Vcmax = -9277.78 N +Mcmax = 54,222.22 N-m