athessMost Watched Ani...A pharmaceutical company claims their new diabetes medication results in less variance in apatient's glucose level than if the patient were on no medication at all. An endocrinologist wishes totest this claim. She divides participants randomly into two groups. Group A consists of 20 diabeticswho received the medication; group B consists of 26 diabetics who received a placebo. After twoweeks, the blood sugar level of each patient in each group was measured with the following results(in mg/dL):Group A:77.8, 229.4, 199.9, 110.1, 180.2, 116.1, 139.7, 171.1, 37.4, 158.1, 88.4, 195.5, 246.1, 142.4, 178.1,105.5, 179.6, 146.1, 78.8, 123.7Group B:124.5, 130.1, 136, 162.8, 113.4, 72.8, 142.6, 50.3, 179.8, 197, 230, 194.3, 171, 109.3, 114.4, 107.5,114.7, 195.3, 127.7, 126.4, 85.6, 166.7, 182.3, 113.5, 216.7, 162.8Ho:Perform a hypothesis test using a 6% level of significance to test the pharmaceutical company'sclaim.Step 1: State the null and alternative hypotheses.H₂:EV 1Watch Invincible S...V 1(So we will be performing a left-tailedWe will use a(n) FdfA= 19Part 2 of 4Step 2: Assuming the null hypothesis is true, determine the features of the distribution oftest statistics.p-value = 0.8103Step 3: Find the p-value of the test statistic.P(FSV 1.45070Chinese bureaucratsot western elementscal skill while retaining✓and denominator degrees of freedom dƒB = 25✓✓distribution with numerator degrees of freedomA = 145.2✓✓test.)SA 53.84✓Pokemon Jigglypu...s²F = =14507083=0.8103Step 4: Make a Conclusion About the null hypothesis.Since the p-value = 0.810308598606662 0.1897IB = 143.365SB 44.7005Yxa, we do not rejectYPart 3 of 4Part 4 of 4✓✓the null hypothesis.We cannot conclude that the medication results in lower variance in a diabetic's blood sugar levels.OWe conclude that the medication results in lower variance in a diabetic's blood sugar levels.tokyo L

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Given that, A pharmaceutical company claims their new diabetes medication results in less variance…

Step 4: Make a Conclusion About the null hypothesis. Since the p-value= 0.81030859860666 2 0.1897 xa, we do not reject Part 4 of 4 the null hypothesis. We cannot conclude that the medication results in lower variance in a diabetic's blood sugar levels.