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Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. A soil layer consists of 4 meters of sand underlying 5 meters

Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. A soil layer consists of 4 meters of sand underlying 5 meters

Principles of Geotechnical Engineering (MindTap Course List)
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter17: Subsoil Exploration
Section: Chapter Questions
Problem 17.14P
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1. Consider Figure FTR 1 (Taken from Geotechnical Engineer- ing Design, Ming Xiao, strictly for educational purposes) shown. If the specific gravity of the soils are respectively from top to bottom 2.6, 2.7 and 2.73, estimate the effec- tive stresses at the mid thickness of each layer. 2. Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. 3. A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is naturally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to de- velop due to the nature of the soil in question. Compute the effective stresses at the end of expected capillary ac- Q = 900 kN Ground surface D; = 1 m Ground water table L× B = 3m × 2m eo=0.5, cc = 0.35, c, = 0.06, ơʻ,= 75 kN/m² Cs Hj = 1m H=9 m eo = 0.48, c¸ = 0.33, c¸= 0.05, ơʻ= 100 kN/m² H2= 2 m eo=0.45, c. = 0.30, c, = 0.05, o. = 180 kN/m² H3= 6m tion, at the end of the water table, at the interface of the clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows: Figure FTR 1 Average S, Capil- lary Zone G, e D10 Clay 2.71 0.98 0.0125 25 55% Sand 2.74 0.93 N.A. N.A. N.A.
Transcribed Image Text:1. Consider Figure FTR 1 (Taken from Geotechnical Engineer- ing Design, Ming Xiao, strictly for educational purposes) shown. If the specific gravity of the soils are respectively from top to bottom 2.6, 2.7 and 2.73, estimate the effec- tive stresses at the mid thickness of each layer. 2. Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. 3. A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is naturally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to de- velop due to the nature of the soil in question. Compute the effective stresses at the end of expected capillary ac- Q = 900 kN Ground surface D; = 1 m Ground water table L× B = 3m × 2m eo=0.5, cc = 0.35, c, = 0.06, ơʻ,= 75 kN/m² Cs Hj = 1m H=9 m eo = 0.48, c¸ = 0.33, c¸= 0.05, ơʻ= 100 kN/m² H2= 2 m eo=0.45, c. = 0.30, c, = 0.05, o. = 180 kN/m² H3= 6m tion, at the end of the water table, at the interface of the clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows: Figure FTR 1 Average S, Capil- lary Zone G, e D10 Clay 2.71 0.98 0.0125 25 55% Sand 2.74 0.93 N.A. N.A. N.A.
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