Straight-chain, saturated carboxylic acids, a class of hydrocarbons, has the general formula CH20+1COOH where n is an integerthan ranges from 1 to 18. What would be the %C by mass if n = 6 ?Atomic weights: C=12.01, H=1.01, O=15.99.Input values only with 2 decimal places. Do not include the units.Add your answer

Given is saturated carboxylic acid CnH2n+1COOH. With n = 6 Atomic weights as C = 12.01 g H = 1.01 g…

Answered: Straight-chain, saturated carboxylic…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Straight-chain, saturated carboxylic acids, a class of hydrocarbons, has the general formula CnH2n+1COOH where n is an integer than ranges from 1 to 18. What would be the %C by mass if n = 1 ?    Atomic weights: C=12.01, H=1.01, O=15.99. Input values only with 2 decimal places. Do not include the units.
The combustion of ammonia in the presence of excess oxygen yields NO2 and H2O:                         4 NH3 (g) + 7 O2 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 161 g of ammonia consumes __________ g of oxygen. atomic weights: N = 14.01, H = 1.01, O = 15.99. Input values only with two decimal places. Do not include the units.
Straight-chain, saturated carboxylic acids, a class of hydrocarbons, have the general formula CnH2n+1COOH where n is an integer that ranges from 1 to 18. What would be the %C by mass if n = 8?    Atomic weights: C = 12.01, H = 1.01, O = 15.99. Input values only with two decimal places. Do not include the units.
The combustion of ammonia in the presence of excess oxygen yields NO2 and H2O: 4 NH3 (g) + 7 O2 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 261 g of ammonia consumes __________ g of oxygen. Atomic weights: N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.
The molecular formula for potassium hydrogen phthalate (abbreviated KHP) is C8H5O4K. What is the molar mass of KHP? Show all work with no rounding errors and have the finalanswer accurate to at least two decimal places.
As part of the aspirin synthesis lab the orgo students also had to perform the following calculation to demonstrate their knowledge. Are you able to help them work this out? Saponification is a process in which soap is produced from the chemical reaction between animal fat (triglycerides) and a strong base such as KOH. An example of such balanced chemical reaction is shown here: C51H98O6 + 3KOH → C3H5(OH)3 + 3C16H31O2K (Triglyceride) (Soap) if during the saponification reaction 231.5 g of C51H98O6 is mixed with 231.5 g of KOH and 160 g of soap is produced. Calculate the theoretical yield of soap C16H31O2K and indicate who is the limiting reactant. (Provide your answer to 2 decimal places) Calculate the percent yield for this reaction (Provide your answer to 1 decimal place) *Show ALL steps and mathematical equations involved in your calculations to help the orgo students. Remember to label all…
After performing precipitation gravimetry, Asta placed the weighing form inside the crucible, heated it, cooled it down, and weighed the crucible with the weighing form and obtained a mass of 23.4120 g. Repeating this cycle continuously gave a mass of 23.2125 g, then 23.1136 g, then 23.1139 g. Which among these masses should he use for his calculations? 23.1136 g 23.2125 g 23.4120 g 23.1139 g
7. After performing precipitation gravimetry, Asta placed the weighing form inside the crucible, heated it, cooled it down, and weighed the crucible with the weighing form and obtained a mass of 23.4120 g. Repeating this cycle continuously gave a mass of 23.2125 g, then 23.1136 g, then 23.1139 g. Which among these masses should he use for his calculations?
What will be the resulting percentage (w/w) of the said syrup if 300 g /2L of sucrose will be used? Density of syrup is 1.313 g/mL. Master Formula Sucrose 850g; Purified water qs ad 1000mL a 9.62 % b 8.9% c 11.42 % d 5.63% e 10.62 %
I am trying to ascertain the density of 0.9-M HCl. The book provides a density of 1.0-M HCl as 1.016g/mL. I know the Molecular Weight aka Molar Mass is 36.46g/mol I also know that the equation to calculate the density in this instand is: Density=(Molarity x Molecular Weight)/WeightI have found examples online, and one answer provided here that shows the Density of 0.9-M HCl is 0.9115g/mL. That answer was arrived at as follows:Density = (0.9M x 36.46g/mol)/36 = 32.814/36 = 0.9115g/mL My problem is that I don't understand where the 36 came from for "weight", and I need to be able to show all unit measurements for each step. So my issue has 2 parts: 1) How was the Weight value determined to be 36 (I need to see the formula)2) Where in the step-by-step process is mL in there so that after all cancellations/conversions are completed, the only remaining units are g/mL to show how 0.9115g/mL was arrived at.
Analytical chemist from Petroleum Development Oman extracted petroleum from crude oil and measured the quantity lost by the extraction to tell how much of the petroleum was . Quantity of Petroleum lost %): 10.8, 11.6, 9.4, 7.8, 9.2, 9.1 , 10.6, 11.6 Should the value 7.8 be rejected from the set of the above results.
A mixture containing only Al2O3 (FM 101.96) and Fe2O3 (FM 159.69) weighs 2.019 g. When heated under a stream of H2, the Al2O3 is unchanged, but the Fe2O3 is converted to metallic Fe plus H2O(g). If the residue weighs 1.774 g, what is the weight percent of Al2O3 in the original mixture? (Do not include % symbol in your answer.)

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