just need help fixing line 10 of code. spacing errorJAVA String personName is read from input. Output "Alex ", followed by personName with a width of 7. End with a newline.Ex: If the input is Thomas, then the output is:Alex Thomas1 import java.util.Scanner;23 public class Output Formatter {45678public static void main(String[] args) {Scanner scnr = new Scanner (System.in);String personName;personName = scnr.next();910 System.out.printf("Alex %s %n", personName);11121314}Check}1Next level2X 1: Compare outputFor input Thomas, the number of characters is 6. The width of 7 is applied to the string, padding the string with 1 space, resultingin "Thomas". "Alex " is output, followed by "Thomas". The output ends with a newline.Not all tests passed.3Output is nearly correct, but whitespace differs. See highlights below. Special character legend

The question tells to insert 2 spaces between Alex and the input.In your code only one space is…

String personName is read from input. Output "Alex", followed by personName with a width of 7. End with a newline. Ex: If the input is Thomas, then the output is: Alex Thomas 1 import java.util.Scanner; 2 3 public class Output Formatter { 4 5 6 7 8 9 10 11 personName= scnr.next(); System.out.printf("Alex %s%n", personName); 12 13 14} public static void main (String[] args) { Scanner scnr = new Scanner (System.in); String personName; Check } 1 Next level 2 3 For input Thomas, the number of characters is 6. The width of 7 is applied to the string, padding the string with 1 space, resu in "Thomas". "Alex " is output, followed by Thomas". The output ends with a newline. Not all tests passed. X 1: Compare output Output is nearly correct, but whitespace differs. See highlights below. Special character legend

String personName is read from input. Output "Alex", followed by personName with a width of 7. End with a newline. Ex: If the input is Thomas, then the output is: Alex Thomas 1 import java.util.Scanner; 2 3 public class Output Formatter { 4 5 6 7 8 9 10 11 personName= scnr.next(); System.out.printf("Alex %s%n", personName); 12 13 14} public static void main (String[] args) { Scanner scnr = new Scanner (System.in); String personName; Check } 1 Next level 2 3 For input Thomas, the number of characters is 6. The width of 7 is applied to the string, padding the string with 1 space, resu in "Thomas". "Alex " is output, followed by Thomas". The output ends with a newline. Not all tests passed. X 1: Compare output Output is nearly correct, but whitespace differs. See highlights below. Special character legend

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter9: Records (struct)

Section: Chapter Questions

Problem 2PE

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