student crosses a pure-breeding line of red-flowered poinsettias with a pure-breeding line of white-flowered poinsettias. The student observes that all the pants in the F1 Generation have pin flowers. The student then crosses the F1 plants with one another and records the observations a the plants in the F2 generation. The student will use the F2 data to perform a chi-square goodne fit test for a model of incomplete dominance. The setup for the student's chi-square goodness c test is presented in table 1. Table 1. A chi-square goodness-of-fit test for incomplete dominance Phenotype Red flowers Pink flowers White flowers Observed 64 107 53 Expected 56 112 56 The critical value for a chi-square test with a significance level of p= 0.05 and 2 degrees of 5.99. Which of the following statements best completes the student's chi-square test? a. The calculated chi-square value is 1.53, and the null hypothesis cannot be rejected. b. The calculated chi-square value is 1.53, and the null hypothesis can be rejected. The calculated chi-square value is 98, and the null hypothesis cannot be rejected. d. The calculated chi-square value is 98, and the null hypothesis can be rejected. C.
student crosses a pure-breeding line of red-flowered poinsettias with a pure-breeding line of white-flowered poinsettias. The student observes that all the pants in the F1 Generation have pin flowers. The student then crosses the F1 plants with one another and records the observations a the plants in the F2 generation. The student will use the F2 data to perform a chi-square goodne fit test for a model of incomplete dominance. The setup for the student's chi-square goodness c test is presented in table 1. Table 1. A chi-square goodness-of-fit test for incomplete dominance Phenotype Red flowers Pink flowers White flowers Observed 64 107 53 Expected 56 112 56 The critical value for a chi-square test with a significance level of p= 0.05 and 2 degrees of 5.99. Which of the following statements best completes the student's chi-square test? a. The calculated chi-square value is 1.53, and the null hypothesis cannot be rejected. b. The calculated chi-square value is 1.53, and the null hypothesis can be rejected. The calculated chi-square value is 98, and the null hypothesis cannot be rejected. d. The calculated chi-square value is 98, and the null hypothesis can be rejected. C.
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter5: The Inheritance Of Complex Traits
Section: Chapter Questions
Problem 7QP: Sunflowers with flowers 10 cm in diameter are crossed with a plant that has 20-cm flowers. The F1...
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