student crosses a pure-breeding line of red-flowered poinsettias with a pure-breeding line of white-flowered poinsettias. The student observes that all the pants in the F1 Generation have pin flowers. The student then crosses the F1 plants with one another and records the observations a the plants in the F2 generation. The student will use the F2 data to perform a chi-square goodne fit test for a model of incomplete dominance. The setup for the student's chi-square goodness c test is presented in table 1. Table 1. A chi-square goodness-of-fit test for incomplete dominance Phenotype Red flowers Pink flowers White flowers Observed 64 107 53 Expected 56 112 56 The critical value for a chi-square test with a significance level of p= 0.05 and 2 degrees of 5.99. Which of the following statements best completes the student's chi-square test? a. The calculated chi-square value is 1.53, and the null hypothesis cannot be rejected. b. The calculated chi-square value is 1.53, and the null hypothesis can be rejected. The calculated chi-square value is 98, and the null hypothesis cannot be rejected. d. The calculated chi-square value is 98, and the null hypothesis can be rejected. C.

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter5: The Inheritance Of Complex Traits
Section: Chapter Questions
Problem 7QP: Sunflowers with flowers 10 cm in diameter are crossed with a plant that has 20-cm flowers. The F1...
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student crosses a pure-breeding line of red-flowered poinsettias with a pure-breeding line of
white-flowered poinsettias. The student observes that all the pants in the F1 Generation have pink
flowers. The student then crosses the F1 plants with one another and records the observations about
the plants in the F2 generation. The student will use the F2 data to perform a chi-square goodness of
fit test for a model of incomplete dominance. The setup for the student's chi-square goodness of fit
test is presented in table 1.
a.
b.
Table 1. A chi-square goodness-of-fit test for incomplete dominance
Phenotype
Red flowers
Pink flowers
White flowers
Observed
64
107
53
Expected
56
112
56
The critical value for a chi-square test with a significance level of p= 0.05 and 2 degrees of freedom is
5.99. Which of the following statements best completes the student's chi-square test?
The calculated chi-square value is 1.53, and the null hypothesis cannot be rejected.
The calculated chi-square value is 1.53, and the null hypothesis can be rejected.
The calculated chi-square value is 98, and the null hypothesis cannot be rejected.
d. The calculated chi-square value is 98, and the null hypothesis can be rejected.
C.
tation 6: Meiosis
Transcribed Image Text:student crosses a pure-breeding line of red-flowered poinsettias with a pure-breeding line of white-flowered poinsettias. The student observes that all the pants in the F1 Generation have pink flowers. The student then crosses the F1 plants with one another and records the observations about the plants in the F2 generation. The student will use the F2 data to perform a chi-square goodness of fit test for a model of incomplete dominance. The setup for the student's chi-square goodness of fit test is presented in table 1. a. b. Table 1. A chi-square goodness-of-fit test for incomplete dominance Phenotype Red flowers Pink flowers White flowers Observed 64 107 53 Expected 56 112 56 The critical value for a chi-square test with a significance level of p= 0.05 and 2 degrees of freedom is 5.99. Which of the following statements best completes the student's chi-square test? The calculated chi-square value is 1.53, and the null hypothesis cannot be rejected. The calculated chi-square value is 1.53, and the null hypothesis can be rejected. The calculated chi-square value is 98, and the null hypothesis cannot be rejected. d. The calculated chi-square value is 98, and the null hypothesis can be rejected. C. tation 6: Meiosis
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