Subtract each element in origList with the corresponding value in offsetAmount. Print each difference followed by a space. Ex: If the input is: 4 5 10 12 2 4 7 3 the output is: 2 1 3 9 1 #include 2 3 int main(void) { const int NUM VALS = 4; int origlist[NUM_VALS]; int offsetAmount[NUM_VALS]; int i; 4 7 8 scanf("%d", &origList[0]); scanf ("%d", &origList[1]); scanf("%d", &origList[2]); scanf("%d", &origList[3]); 10 11 12 13 scanf ("%d", &offsetAmount[0]); scanf("%d" scanf("%d", &offsetAmount[2]); scanf ("%d", &offsetAmount[3]); 14 15 &offsetAmount[1]); 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }
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- Subtract each element in origList with the corresponding value in offsetAmount. Print each difference followed by a space. Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print: 2 1 3 9 #include <iostream>#include <string.h>using namespace std; int main() { const int NUM_VALS = 4; int origList[NUM_VALS]; int offsetAmount[NUM_VALS]; int i; cin >> origList[0]; cin >> origList[1]; cin >> origList[2]; cin >> origList[3]; cin >> offsetAmount[0]; cin >> offsetAmount[1]; cin >> offsetAmount[2]; cin >> offsetAmount[3]; /* Your code goes here */ cout << endl; return 0;}Ludo Ladders Game(C++)Structural code is given below of the project.Few parts of the code is removed and comments are added, you need to complete the code.#pragma warning(disable:4996)#include <iostream> #include <stdio.h> #include <stdlib.h>#include <time.h>using namespace std;struct Ludo{int Game[100];// This array contains the position of ladders and snakes in the game// If the position contains a +ve number then there is a ladder at that position// If the position contains a -ve number then there is a snake at that positionint Turn = 0;int position[2];int state = -1;};int Roll(){/**use rand() function from Math.hThis function will roll a dice. The rules for dice roll are as follows.If the player roles a six then he gets an other turn.If he rolls three sixes then his score becomes zero but if he rolls more than three sixes then all rolls count.*/srand(time(0));int i;int n = 6;for (i = 0; n == 6; i++){if (i == 0){n = rand() % 6 + 1;}else if (n == 18){n =…Ludo Ladders Game(C++)Structural code is given below of the project.Few parts of the code is removed and comments are added, you need to complete the code.#pragma warning(disable:4996)#include <iostream>#include <stdio.h>#include <stdlib.h>#include <time.h>using namespace std;struct Ludo{int Game[100];// This array contains the position of ladders and snakes in the game// If the position contains a +ve number then there is a ladder at that position// If the position contains a -ve number then there is a snake at that positionint Turn = 0;int position[2];int state = -1;};int Roll(){/**use rand() function from Math.hThis function will roll a dice. The rules for dice roll are as follows.If the player roles a six then he gets an other turn.If he rolls three sixes then his score becomes zero but if he rolls more than three sixes then all rolls count.*/srand(time(0));int i;int n = 6;for (i = 0; n == 6; i++){if (i == 0){n = rand() % 6 + 1;}else if (n == 18){n =…
- an int variable k, an int array currentMembers that has been declared and initialized, an int variable nMembers that contains the number of elements in the array, an int variable memberID that has been initialized, and a bool variable isAMember, Write code that assigns true to isAMember if the value of memberID can be found in currentMembers, and that assigns false to isAMemberotherwise. Use only k, currentMembers, nMembers, and isAMember.#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…
- Array TypesObjective: Based on the given values and initializations, give what is being required of each statement.1. Given A[10], α=2000, esize=4 bytes:a) Find the number of elements.b) Find the address of the 6th element.c) Find the index no. of the 8th element.2. Given E[3][4], α=2020, esize=4 bytes:a) Find the total no. of elements.b) Find the address of the last element.c) Find the address of the 10th element.Consider the following structure and declarations: struct Player { string firstName; string lastName; int hits; int runs; }; int main() { Player p = { "Jackie", "Robinson", 1518, 947 }; Player team[24]; Player *tPtr = team; team[0] = p; // INSERT CODE HERE } The statement tPtr = *team; will assign the memory address of the first element of team array to tPtr **Notice the star in *team, that way its accurate*** A.) True B.) FalseFor any element in keysList with a value smaller than 40, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If keysList = {32, 105, 101, 35} and itemsList = {10, 20, 30, 40}, print: 10,40, #include <iostream>#include <string.h>using namespace std; int main() { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; cin >> keysList[0]; cin >> keysList[1]; cin >> keysList[2]; cin >> keysList[3]; cin >> itemsList[0]; cin >> itemsList[1]; cin >> itemsList[2]; cin >> itemsList[3]; /* Your code goes here */ cout << endl; return 0;}
- Visual Basic.net) Write a Code that defines one dimensional arrays of ten elements that sums the even numbers from them and a counter that counts how many elements is an even number and comes out from the Loop when the sum of the even values becomes greater than 30 and the counter for these values is greater than 4. Write a program in Visual Basic.net .Look at the following array definition: String[ ] sArray = new String[3]; a. What will be returned by sArray.length when printed to screen b. What subscript should be used to access the last element in this array? c. Can we save integer elements in this array?2.2 A struct employeeType has been declared with two elements: name and salary.a. Declare an employeeType struct array for 100 employees. b. Write a code snippet of the loop that will accept the details of the 100 employees.