Supply the missing parts Given: AT = BC CO bisects ZACB Prove: AACO = ABCO Proof: Since, AC = BC, CO bisects LACB, Hence ZACO = LBCO by the 1, property. Thus, We have AC BC. LACO ZBCO, CO CO. then AACO AHCO by 3. Also 2. by reflexive

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Chapter2: Parallel Lines
Section2.4: The Angles Of A Triangle
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Answer the blank in the statement. Answer number 1 only. 

Supply the missing parts.
Given: AC = BC
CO bisects ZACB
Prove: AACO = ABCO
Proof: Since, AC = BC, CO bisects LACB, Hence ACO = LBCO by the
Also 2.
by reflexive
property. Thus, We have AC = BC, LACO e ZBCO, CO = CO,
then AACO AHCO by 3.
Transcribed Image Text:Supply the missing parts. Given: AC = BC CO bisects ZACB Prove: AACO = ABCO Proof: Since, AC = BC, CO bisects LACB, Hence ACO = LBCO by the Also 2. by reflexive property. Thus, We have AC = BC, LACO e ZBCO, CO = CO, then AACO AHCO by 3.
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