Supply the missing statement and reasons to complete the proof. 7. Given: mZ2 > mZ1 Prove: mz2> mZ4 Statements Reasons 1. 1. 2. mz1 > mZ3 2. 3. m/2 > mZ3 3. 4. m23 = mZ4 4. 5. 5.
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- Conduct the hypothesis test for H0: µ = 10 versus Ha: µ =/10 (i.e µ is not equal to 10) where x bar = 9.6 and s = 3, n = 50. Use alpha = .01. Explain whether we should reject or accept the null hypothesis.Here are the choices: >The defective/nondefective classification depends on machinist classification >10.88 >Failed to reject the null >11.2 >2 >The defective/nondefective classification is independent on machinist classification >Reject the null >3Plz answer both questions Answers: 2. Fobt= 10.08, reject H0, do Wilcoxon; Zobt = 1.197, do not reject Ho 3. t =0.163, Do not reject Ho; no evidence that the device increases cars' mpg
- 4. The lifetime, in years, of a type of small electric motor operating under adverse conditions is T ~Γ(6, 3.6). Whenever the motor fails, it is replaced with another of the same type. Find theprobability that fewer than 6 motors fail within one year.Answers: 1. Fobt = 7.54, reject H0;, do Wilcoxon; Tobt = 90.5, reject H0 2. Fobt = 10.08, reject H0, do Wilcoxon; Zobt = 1.197, do not reject H0 3. t = .163, Do not reject H0; no evidence that the device increases cars' mpgfind 1. Z value 2. P Value 3. T value 4. Reject or do not reject 5. State conclusion
- The old drug treatment for a specific type of cancer produced a five year survival rate of 15 to 1,000. In a sample of a new drug, the survival rate is 45 per 1,000. Has there been an increase in the overall survival rate with new drug? The null and alternative hypotheses are: H subscript 0 colon space M equals 15 space a n d space H subscript 1 colon space M equals 45 H subscript 0 colon space M equals 45 space a n d space H subscript 1 colon space M equals 15 H subscript 0 colon space M equals 15 space a n d space H subscript 1 colon space M greater than 15 H subscript 0 colon space M less than 15 space space a n d space H subscript 1 colon space M equals 45 space H subscript 0 colon space M less than 15 space space a n d space H subscript 1 colon space M element of 15 spaceIf a particle is moving with v(x)=1.5(x^1/2) and s(9)=33, what is the position of the particle? As a sidenote, this question is about antiderivatives.If we had a directional hypothesis, Critical value of tcv= 2.15 and Obtained value of tobt=-2.20. What conclusion would we draw based on these results? 1)Reject Ha 2)Reject H0 3)Prove Ha 4) fail to reject H0
- The article “Can We Really Walk Straight?” (Amer. J.of Physical Anthropology, 1992: 19–27) reported on anexperiment in which each of 20 healthy men was askedto walk as straight as possible to a target 60 m away atnormal speed. Consider the following observations oncadence (number of strides per second):.95 .85 .92 .95 .93 .86 1.00 .92 .85 .81.78 .93 .93 1.05 .93 1.06 1.06 .96 .81 .96Use the methods developed in this chapter to summarizethe data; include an interpretation or discussion whereverappropriate. [Note: The author of the article used a rathersophisticated statistical analysis to conclude that peoplecannot walk in a straight line and suggested severalexplanations for this.]Fivereadings of theresistance, in ohms, of apiece of wire gave thefollowing results:1.51,1.49, 1.54, 1.52,1.54. Ifthe wire were puresilver, its resistancewould be 1.50ohms. Ifthe wire were impure,the resistance would beincreased. If theprobability of type Ierror is 5%, test thehypothesis that thewire is pure silveIs there a way to solve this w/o using L'Hospital's rule?