Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: milliamperes The total amount of charge passing through the filament in t= 5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 × 10¬19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons

Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: milliamperes The total amount of charge passing through the filament in t= 5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 × 10¬19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter9: Current And Resistance

Section: Chapter Questions

Problem 24P: A conductor carries a current that is decreasing exponentially with time. The current is modeled as...

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