Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: I = ____________ milliamperes The total amount of charge passing through the filament in t = 5.00 s end text is: Q = ____________ coulombs Since a single electron has a charge of -1.60 x 10-19C, the number of electrons passing through the filament in t = 5.00 s end text is: N = ____________ x 1019 electrons
Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: I = ____________ milliamperes The total amount of charge passing through the filament in t = 5.00 s end text is: Q = ____________ coulombs Since a single electron has a charge of -1.60 x 10-19C, the number of electrons passing through the filament in t = 5.00 s end text is: N = ____________ x 1019 electrons
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter21: Current And Direct Current Circuits
Section: Chapter Questions
Problem 17P
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Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures.
The current in the light bulb is:
I = ____________ milliamperes
The total amount of charge passing through the filament in t = 5.00 s end text is:
Q = ____________ coulombs
Since a single electron has a charge of -1.60 x 10-19C, the number of electrons passing through the filament in t = 5.00 s end text is:
N = ____________ x 1019 electrons
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