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Suppose a car travels 108 km at a speed of 35.0 m/s, and uses 1.80 gallons of gasoline. Only 30% of the gasoline goes into useful work by the force that keeps the car moving at constant speed despite friction. (The energy content of gasoline is 1.3 ✕ 108 J per gallon.)(a) What is the force exerted to keep the car moving at constant speed?  N(b) If the required force is directly proportional to speed, how many gallons will be used to drive 108 km at a speed of 28.0 m/s?  gallons

Question

Suppose a car travels 108 km at a speed of 35.0 m/s, and uses 1.80 gallons of gasoline. Only 30% of the gasoline goes into useful work by the force that keeps the car moving at constant speed despite friction. (The energy content of gasoline is 1.3 ✕ 108 J per gallon.)(a) What is the force exerted to keep the car moving at constant speed?
  N

(b) If the required force is directly proportional to speed, how many gallons will be used to drive 108 km at a speed of 28.0 m/s?
  gallons

check_circleAnswer
Step 1

(a). The amount of work done to keep the car moving at constant speed can be calculated as follows,

W (1.80 gallons)1.3 x 10 Jper gallons)(0.30)
- 7.02 x107 J
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W (1.80 gallons)1.3 x 10 Jper gallons)(0.30) - 7.02 x107 J

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Step 2

Write the expression for work done, substitute the corresponding values, an...

W Fd
7.02x 10 J Fx (108x10 m)
F 650N
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W Fd 7.02x 10 J Fx (108x10 m) F 650N

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