Suppose among a population of students 50% own a laptop and 30% of the total have a laptop but no tablet. Suppose 70% have a laptop, a tablet, or both. Are the probabilities of owning a laptop and a tablet independent? No, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.2 x 0.5 = f(tablet & laptop) Cannot answer given the info No, pr(tablet) x pr(laptop) = 0.45 x 0.5 != f(tablet & laptop)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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Suppose among a population of students 50% own a laptop and 30% of the total have
a laptop but no tablet. Suppose 70% have a laptop, a tablet, or both. Are the
probabilities of owning a laptop and a tablet independent?
No, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop)
Yes, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop)
Yes, pr(tablet) x pr(laptop) = 0.2 x 0.5 = f(tablet & laptop)
Cannot answer given the info
No, pr(tablet) x pr(laptop) = 0.45 x 0.5 != f(tablet & laptop)
Transcribed Image Text:Suppose among a population of students 50% own a laptop and 30% of the total have a laptop but no tablet. Suppose 70% have a laptop, a tablet, or both. Are the probabilities of owning a laptop and a tablet independent? No, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.2 x 0.5 = f(tablet & laptop) Cannot answer given the info No, pr(tablet) x pr(laptop) = 0.45 x 0.5 != f(tablet & laptop)
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