Suppose an electron (q= -e= - 1.6 x 10-19 C,m=9.1 x 1031 kg) is accelerated from rest through a potential o-31 difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U=0

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
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Suppose an electron (q= - e= - 1.6 × 10-19 C,m= 9.1 x 10-31 kg) is accelerated from rest through a potential
difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K= -U
Transcribed Image Text:Suppose an electron (q= - e= - 1.6 × 10-19 C,m= 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K= -U
1
Since K
mv and using the formula for potential energy above, we arrive at an equation for speed:
2
1/2
V = (
Plugging in values, the value of the electron's speed is:
x 107 m/s
Transcribed Image Text:1 Since K mv and using the formula for potential energy above, we arrive at an equation for speed: 2 1/2 V = ( Plugging in values, the value of the electron's speed is: x 107 m/s
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